Advertisement

06.02.2008 at 09:04AM PDT, ID: 23450324
[x]
Attachment Details
[x]
The Solution Rating System

With so many solutions, how can you tell which solutions are most likely to help you and which ones are not? To provide you with a tool to use, we rate our solutions based on various elements that most accurately determine if a solution is a quality solution. To explain what factors affect the solution rating, here are the elements we take into consideration when formulating our solution rating.

  • The Grade of the Solution
  • The Zone Rank of the Expert Providing the Solution
  • The Number of Author and Expert Comments
  • The Number of Experts Contributing
  • The Feedback of the Community

Your Input Matters
Because of the way the system is set up, the most important variable in this equation is you. As a member of Experts Exchange, you are able to cast your vote on the quality of the solutions in regard to how complete, accurate, helpful and easy to understand each solution is. When you provide your feedback, each rating is adjusted accordingly. So, if you see a solution that has a poor rating that you think is a good solution, let us know by rating it. As you do, the rating will be adjusted and will become more accurate for other members of our site.

If you have any suggestions that you would like to make for our rating system, please ask a question in the Suggestions Zone of Community Support.

Thank you!

8.2

sql not in derived table

Asked by dchau12 in SQL Server 2005

I am trying to compare a list of string from a notepad file to the values stored in the column of a table.  I want to find the string from notepad that do not exist in the table.  I could import the list of strings into a temporary table, and then write something like this to find the values that dont exist:

Select MyString
From tableA
where MyString not in ( select tempString from TableTemp)

How can I do this without going through the hassle importing the values from notepad and then comparing the tables?  I imagine I would create a derived table, but I'm not sure how to go about it.

Thanks,

Ryan
Start Free Trial
[+][-]06.02.2008 at 11:49AM PDT, ID: 21694465

View this solution now by starting your 14-day free trial. Setting up your free trial is quick, easy, and secure. We will return you to this solution, unlocked, when you're done.

 

About this solution

Zone: SQL Server 2005
Sign Up Now!
Solution Provided By: angelIII
Participating Experts: 1
Solution Grade: A
 
 
 
Loading Advertisement...
20081112-EE-VQP-43 / EE_QW_2_20070628