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06/12/2009 at 04:49AM PDT, ID: 24486295
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6.6

How do I filter a select query?

Asked by Shepwedd in SQL Server 2005

Tags: sql, sql server 2005, tsql

I have written the attached select query. How can I alter it so my results only return the columns that do not contain the value '[email]'?

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Select Distinct iaaFirst.InterviewerEmail, iaaSecond.InterviewerEmail, iaaThird.InterviewerEmail,
      'This is a reminder that you have the below interview on ' + CONVERT(NVARCHAR(19), aai.InterviewDate, 103) + ':' + CHAR(13) + CHAR(13) + 'Vacancy Title: ' + vvd.Title + CHAR(13) + 'Job Level: ' + vjll.JobLevelDescription + CHAR(13) + 'Job Status: ' + vjsl.JobStatusDescription + CHAR(13) + 'Job Type: ' + vjtl.JobTypeDescription + CHAR(13) + 'Division: ' + vdl.DivisionDescription + CHAR(13) + 'Office: ' + vol.OfficeDescription + CHAR(13) + 'Closing Date: ' + CONVERT(NVARCHAR(10), vvd.ClosingDate, 103) + CHAR(13) + CHAR(13) + 'Applicant: ' + aad.Salutation + ' ' + aad.FirstName + ', ' + aad.LastName + CHAR(13) + 'Address: ' + aad.Address + CHAR(13) + 'Phone Number: ' + aad.Phone + CHAR(13) + 'Email Address: ' + aad.Email + CHAR(13) + CHAR(13) + 'First Interviewer: ' + iaaFirst.Salutation + ' ' + iaaFirst.InterviewerFirstName + ', ' + iaaFirst.InterviewerLastName + '(Email: mailto:' + iaaFirst.InterviewerEmail + ' ' + 'Phone: ' + iaaFirst.InterviewerPhone + ')' + CHAR(13) + 'Second Interviewer: ' + iaaSecond.Salutation + ' ' + iaaSecond.InterviewerFirstName + ', ' + iaaSecond.InterviewerLastName + '(Email: mailto:' + iaaSecond.InterviewerEmail + ' ' + 'Phone: ' + iaaSecond.InterviewerPhone + ')' + CHAR(13) + 'Third Interviewer: ' + iaaThird.Salutation + ' ' + iaaThird.InterviewerFirstName + ', ' + iaaThird.InterviewerLastName + '(Email: mailto:' + iaaThird.InterviewerEmail + ' ' + 'Phone: ' + iaaThird.InterviewerPhone + ')'
From Applicant.ApplicantDetails aad 
INNER JOIN Applicant.ApplicantInterviews aai ON aad.ApplicantID = aai.ApplicantID 
INNER JOIN Applicant.ApplicantInterviewers iaaFirst ON aai.FirstInterviewer = iaaFirst.InterviewerID
INNER JOIN Applicant.ApplicantInterviewers iaaSecond ON aai.SecondInterviewer = iaaSecond.InterviewerID
INNER JOIN Applicant.ApplicantInterviewers iaaThird ON aai.ThirdInterviewer = iaaThird.InterviewerID
INNER JOIN Vacancy.VacancyDetails vvd ON aad.VacancyID = vvd.VacancyID 
INNER JOIN Vacancy.JobLevelLookups vjll ON vvd.JobLevelCode = vjll.JobLevelCode
INNER JOIN Vacancy.JobStatusLookups vjsl ON vvd.JobStatusCode = vjsl.JobStatusCode
INNER JOIN Vacancy.JobTypeLookups vjtl ON vvd.JobTypeCode = vjtl.JobTypeCode
INNER JOIN Vacancy.DivisionLookups vdl ON vvd.DivisionCode = vdl.DivisionCode
INNER JOIN Vacancy.OfficeLookups vol ON vvd.OfficeCode = vol.OfficeCode
[+][-]06/12/09 05:01 AM, ID: 24611239

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About this solution

Zone: SQL Server 2005
Tags: sql, sql server 2005, tsql
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Solution Provided By: chapmandew
Participating Experts: 1
Solution Grade: B
 
 
[+][-]06/12/09 07:22 AM, ID: 24612595

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[+][-]06/15/09 02:10 AM, ID: 24627137

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