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7.0

Get Years, Months and Days between Dates

Asked by tomazsr in SQL Server 2005, SQL Server 2008

Tags: T-SQL, Date Functions

Hi,

I need to get exact difference between two dates in years, months, days.
I try few ideas from internet but its not ok, days are not calc right.

Please for any idea
Tomaz

If I run procedure :
declare @Year int ,
@Month int ,
@Day int


exec CalcYearsMonthsDays
'20060228',
'20090904',
@Year  output,
@Month  output,
@Day  output

print @Year
print @Month
print @Day

I get:
3 years
6 months
7 days

but must be 4 days :0((

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create procedure CalcYearsMonthsDays
@DateFrom datetime,
@DateTo datetime,
@Year int output,
@Month int output,
@Day int output
 
as
set nocount on
 
 
DECLARE @Date 	datetime
SET @Year = 0
SET @Month	= 0
SET @Day	= 0
SET @Date	= @DateFrom
 
--calculate the @Year 
if(datepart(year,@DateTo)>datepart(year,@DateFrom))
begin
    SET @Year = datediff(year,@DateFrom,@DateTo)
    SET @Date = dateadd(year,@Year,@DateFrom)--update runningdate
    if(@Date>@DateTo)
	begin
        SET @Year = datediff(year,@DateFrom,dateadd(year,-1,@DateTo)) --calculate years from @DateFrom to @DateTo - 1 year
        SET @Date = dateadd(year,@Year,@DateFrom)--update runningdate
	end
end
 
 
--add 1 month as long as running date is smaller than or equal to @DateTo
WHILE @Date<=@DateTo
begin
    SET @Date = dateadd(month,1,@Date)
    IF (@Date<=@DateTo)
    begin 
        SET @Month=@Month+1
    end
end
 
--set @Date back 1 month
SET @Date=dateadd(month,-1,@Date)
--start to count days
WHILE @Date<@DateTo
begin
    SET @Date=dateadd(day,1,@Date)
    SET @Day=@Day+1
end
 
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About this solution

Zones: SQL Server 2005, SQL Server 2008
Tags: T-SQL, Date Functions
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Solution Provided By: mark_wills
Participating Experts: 3
Solution Grade: A
 
 
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