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07.01.2008 at 09:18PM PDT, ID: 23532469
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Attachment Details

Public Function to open a form using link criteria from another form

Asked by Ludique in Access Coding/Macros

Tags: VB, Access 2003

I'm trying to create a public function that I can call from a control on any form to open another form and set the link criteria, but I'm stuck on the Link Criteria bit - please see snippet below.
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From the calling form I'd like to use something like this:

Call OpenLinkForm("OrderList", "frmOrder", "OrderID", "OrderID")Start Free Trial 
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Public Function OpenLinkForm(xForm As String, yForm As String, xCtl As String, yCtl As String)
    
       ' xForm is the the calling form
       ' yForm is the form to be opened
       ' xCtl is the control on the calling form to be used as link criteria
       ' yCtl is the control to link to on the form to be opened
        
        stLinkCriteria '=  I need something like  where yForm.yCtl = xForm.xCtl
        
        DoCmd.OpenForm yForm, , , stLinkCriteria
            
 
    End Function
[+][-]07.01.2008 at 11:24PM PDT, ID: 21913901

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About this solution

Zone: Access Coding/Macros
Tags: VB, Access 2003
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Solution Provided By: jpaulino
Participating Experts: 1
Solution Grade: B
 
 
[+][-]07.02.2008 at 10:44AM PDT, ID: 21918824

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[+][-]07.02.2008 at 11:13AM PDT, ID: 21919067

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[+][-]07.04.2008 at 03:37AM PDT, ID: 21932189

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[+][-]07.04.2008 at 03:59AM PDT, ID: 21932283

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[+][-]07.04.2008 at 03:59AM PDT, ID: 21932285

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[+][-]07.22.2008 at 12:34AM PDT, ID: 22057057

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