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6.6

access sql max date max sequence

Asked by toni_ in Access Coding/Macros, SQL Query Syntax

Hi I need to return the latest Job Typ Description and Job Step Desc in an access query based on the Pay Str Date and the sequence number. So looking at the attacment data i should be returning Combo Welder, J/M II. I have a partial query below but i can not figure out how to return the info i need.
Thanks
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SELECT tblEMPData.Number, tblEMPData.Surname, tblEMPData.Name, tblEMPData.Status, tblEMPData.Site, tblEmpProjectHistory.[Job Typ Description 1], tblEmpProjectHistory.[Job Step Description 1], tblEmpProjectHistory.[Sequence Number]
FROM tblEMPData LEFT JOIN (SELECT A.[Address Number], A.[Job Typ Description 1], A.[Job Step Description 1], A.[Sequence Number]
FROM tblEmpProjectHistory as A
WHERE A.[Pay Str Date] = (SELECT Max(B.[Pay Str Date]) FROM tblEmpProjectHistory B WHERE B.[Address Number] = A.[Address Number]))  AS tblEmpProjectHistory ON tblEMPData.[Number] = tblEmpProjectHistory.[Address Number]
ORDER BY tblEMPData.Surname, tblEMPData.Name;
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About this solution

Zones: Access Coding/Macros, SQL Query Syntax
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Solution Provided By: toni_
Participating Experts: 3
Solution Grade: A
 
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