Question

Evaluating checkbox results

Asked by: noclew

Hi Experts.  I'm stumped on this one.  I currently need to build a tool that will evaluate the user's choices in a number of checkboxes.  For this test, I will only use 8 choices.  Based on the results of the individual choices, different suggested activity needs to be displayed.  For instance, if the user chooses choice 1, and choice 5, the individual suggestions1 and suggestions5 need to be displayed.  Also, if there is a grouped suggestion for the choice it needs to be displayed, therefore, if they choose choices 1 and 5, suggestions 1 and 5 need to display, along with the grouped suggestion for the combination of 1 and 5.  I'm making that happen by taking the checkbox choice, multiplying it by -1 and then creating a boolean number.  I then recursively step through the boolean number from right to left to check for the value of each place.  If it's a 1, I push a tag to a field in a record in a table to indicate it should be displayed.  The records in the table are named with a suffix equal to the factor they represent.  I know I don't need to do that and I could just step through the controls, but I use the boolean number to also determine it's decimal equivalent.  That decimal equivalent lets me know what options are chosen as a grouping, which I can then use to check for a corresponding grouped suggestion value.  All this works.  I can increase the number of checkboxes (choices) without impacting the code at all.  I can therefore build a maintenance section for the user to add additional choices and additional suggestions for total groupings and for the individual choices.  What I can't figure out right now (I many be staring right at it!) is how to capture the values for any of the potential sub-groupings so that I may also display those choices.

For instance, choices 1,2,3,4.  Have a total grouping of the four choices.  But there are also the sub-groupings 1 and 2, 1 and 3, 1 and 4, 1 and 2 and 3, 2 and 3 and 4, etc.  It's these values that I also need to capture so that I may display suggested actions for those sub-groupings as well.  Since the potentially chosen options are not necessarily sequential, I can't figure out a way to step through it and capture all the possible values.

If anyone has any ideas, I'd be thrilled to hear them.

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Asked On
2009-11-06 at 08:59:39ID24878519
Tags

vba

,

msaccess

Topics

Access Coding/Macros

,

Microsoft Access Database

,

Microsoft Programming

Participating Experts
3
Points
500
Comments
24

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Answers

 

by: omgangPosted on 2009-11-06 at 11:29:27ID: 25762282

I'm not sure I fully understand how you are flagging records to indicate they need to be displayed but my inititial thought is perhaps you need to attack this from the reverse.  Iterate through all records in the table and see if the conditions necessary for them to be displayed are present on the form.

Example
Table record1 - display if check box 1 is checked
Table record2 - display if check box 2 is checked
Table record3 - display if check box 3 is checked
.
.
.
Table record27 - display if check box 1 is checked AND if check box 5 is checked

Does that make sense?
OM Gang

 

by: DRY_GINPosted on 2009-11-06 at 11:38:08ID: 25762362

basically IF result of ADDING all your checkboxes  to suggestion code equal to suggestion code it should be displayed

I would keep in suggestions table a field with boolean code for suggestions
for example if it a group sugg 1,3,4 the result code should be 0001101 (let's call it qvCode)

now lets say you have checkboxes 1,2,3 - you have to  do a query : where (((qvCode OR 1) OR 2) OR 3) = qvCode

if im not mistaking anything it should work

regards
Alex

 

by: DRY_GINPosted on 2009-11-06 at 11:44:34ID: 25762407

sorry, i made mistakes i have to rewrite it:

basically IF result of ADDING suggestion code to all your checkboxes code is  equal to checkboxes when code it should be displayed

I would keep in suggestions table a field with boolean code for suggestions
for example if it a group sugg 1,3,4 the result code should be 0001101 (let's call it qvCode)

now lets say you have checkboxes 1,2,3  when you boolean encode whem as well , result will be 0000111 - call it checkCode
in query it will be : where (checkCode OR qvCode) = checkCode

hope this time is correct...
Alex


 

by: noclewPosted on 2009-11-06 at 12:03:32ID: 25762554

Hi there.  Thanks for the feedback.  That part is all figured out without incident.  In boolean, let's consider the number 101101.  That's got a decimal equivalent of 45.  By naming my records with a convention that includes a suffix of the decimal values that represent the total grouping, I can push turn the display record flag on or off without any if statements at all.

I'll attach a snippit of code that does this.

My problem is, in the boolean number 101101, there are more than one sub-grouping of choices.  The value 000101, 001101, the value 100001 and others are all valid sub-groupings within the total grouping.  I need to be able to iterate through the boolean number to pick out all the possible decimal values that are represented by places that are turned to 1 within the number.

Again, the code I've posted works without incident.  I'm just not sure how to write in the code for what I describe above as the sub-groupings.

' this code checks to total value of the boolean results decimal equivalent.  Changefield represents the record name prefix plus the decimal equivalent value.
 
ChangeField = "lblWMActivity" & WorkerFactorDecimal
strSQL = "UPDATE tblActivities " & _
            "SET activitystatus = 'x' " & _
            "WHERE activityname = '" & ChangeField & "';"
DoCmd.RunSQL strSQL
 
' Check each character in WorkerFactorBoolean for check mark(1). if found, change tag value to X for later inclusion in message
 
For i = 1 To Len(WorkerFactorBoolean)
    ChangeField = "lblWActivity" & i
    BackwardMid = Len(WorkerFactorBoolean) + 1 - i
    Result = Mid(WorkerFactorBoolean, BackwardMid, 1)
    If Result = "1" Then
        strSQL = "UPDATE tblActivities " & _
                    "SET activitystatus = 'x' " & _
                    "WHERE activityname = '" & ChangeField & "';"
             
        DoCmd.RunSQL strSQL
    End If
Next i

                                              
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by: GRayLPosted on 2009-11-06 at 13:39:53ID: 25763309

Just so we're on the same page, what groups exist in "1011" and "1001"?

 

by: noclewPosted on 2009-11-06 at 13:47:45ID: 25763364

yes.  Both exist within the grouping of 1011.  

 

by: GRayLPosted on 2009-11-06 at 14:11:19ID: 25763521

I wanted to know all the groups in both of those cases

 

by: DRY_GINPosted on 2009-11-06 at 15:44:15ID: 25764083

so is (CheckBoxesBooleanCode OR SUggestionBoleanCode) = CheckBoxesBooleanCode
won't work?

 

by: DRY_GINPosted on 2009-11-06 at 16:12:52ID: 25764238

consider 101 as checkbox code ( 1 and 3 checked)
and assume you have 1,10,11,100,101,110,111 to be table answers
the "(101 or table_value)=101" will result in 1,100 and 101 to be you valid things to display - i think this is what you want..

 

by: GRayLPosted on 2009-11-07 at 11:09:20ID: 25767612

I think I see, but to be clear, I would have written it:  001, 100, and 101

in my case of 1011 that would be - 0001,0010,0011,1000,1001,1010,1011 ??

 

by: noclewPosted on 2009-11-09 at 08:12:24ID: 25777192

Hi there.  I was away over the weekend.  Unfortunately, I'm having a hard time following what you are talking about.  GRayL has it right when it comes to the possible combinations.  I'm now just wondering how to write the code to check for all those possible combinations.

 

by: GRayLPosted on 2009-11-09 at 13:43:17ID: 25780449

The number of combinations is 2^n - 1.  So if 4 of the eight checkboxes is checked, 2^4 - 1 = 15 combinations.  It does not matter which 4 - any four will result in 15 combinations.  The problem is which combinations?  I'm working on it.  Interesting!

Here is how it grows:

1       1
10      10
11      1,10,11
100     100
101     1,100,101
111     1,10,11,100,101,110,111
1000    1000
1001    1,1000,1001
1011    1,10,11,1000,1001,1010,1011
1101    1,100,101,1000,1001,1100,1101
1111    1,10,11,100,101,110,111,1000,1001,1010,1011,1100,1101,1110,1111

 

by: noclewPosted on 2009-11-10 at 11:25:11ID: 25788785

Hi GrayL

Any progress?  I've been working it through a couple of different ways but no success yet.

 

by: GRayLPosted on 2009-11-10 at 14:55:00ID: 25790829

Sorry, I haven't been able to even look at anything today.  I'll give it a shot tomorrow.

 

by: GRayLPosted on 2009-11-11 at 14:35:28ID: 25799900

I'm part way there.  I think I see light at the end of the tunnel - I'm sure its not a train coming from the opposite direction ;-)  More tomorrow

 

by: noclewPosted on 2009-11-11 at 16:06:45ID: 25800488

Thanks GRayL.  It's really an interesting problem.  I'm looking forward to seeing what you come up with!

 

by: noclewPosted on 2009-11-11 at 20:51:23ID: 25801621

It's getting late so maybe I'm off base, but I think this may be close.  I can't test it at home as I run OSX with no VB so I'll have to test tomorrow, but here's the attempt.  Instead of looping through the records as the outer loop, I instead compare all the record's 1 place digit values, then all two place digit combinations, then three place digit combinations, etc.  Once I've looped up to the length of the boolean number, I move to the next record and do it again.  In other words, I check record's Place Value (RPV) 1 to Chosen Place Value (CPV) 1, then RPV2 to CPV2, RPV3 TO CPV3, ETC.  I then check RPV1&2 TO CPV1&2 THEN RPV2&3 to CPV2&3, RPV3&4 to CPV3&4, ETC.  I then check RPV123 to CPV123 THEN RPV234 to CPV234, ETC.  Once all the combinations are checked, I move onto the next record and start again.

I haven't included any of the stuff to build the decimal equivalents or other stuff because that wasn't the point of the problem.

I'll let you know how it goes tomorrow and I'm interested in what you've come up with!

For I = 1 to Len(ChoiceBoolean)
 rs.MoveFirst
 Do while not rs.EOF
  if tblDecimalValue > ChoiceDecVal then
   Showit = "N"
  Else
   For Z = 1 to len(ChoiceBoolean - (I - 1))
    if Showit <> "" then exit do
    if mid(ChoiceBoolean,len(choiceboolean + (1 - Z),I)) =
    mid(tblBoolean,len(choiceboolean + (1 - Z),I)) _
    and if instr(tblBoolean, "1", I) >= 1 then
     showit = "Y"
     exit for
    end if
   next Z
 end if
 rs.MoveNext
 Loop
Next I

                                              
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by: noclewPosted on 2009-11-12 at 11:49:36ID: 25808151

Got it working...

Public Sub trying4()
Dim rs As DAO.Recordset
 
' Set statements
Set rs = DBEngine(0)(0).OpenRecordset("tblActivities")
ChoiceBoolean = WorkerFactorBoolean
 
' Reset all ActivityStatus values to ""
rs.MoveFirst
Do While Not rs.EOF
    With rs
    .Edit
    !ActivityStatus = ""
    .Update
    End With
rs.MoveNext
Loop
rs.MoveFirst
 
 
For i = 1 To Len(ChoiceBoolean)
    rs.MoveFirst
    Do While Not rs.EOF
    tblboolean = rs!ActivityShowBoolean
    tblConvertNumber = rs!ActivityShowBoolean
    tblDecimalValue = 0
    Showit = rs!ActivityStatus
        ' Determine the total decimal value tblActivities.ActivityShowBoolean
        For W = 1 To Len(tblboolean)
            If tblConvertNumber = "" Then Exit For
            If W = 1 Then
                tblDecimalValue = (tblDecimalValue) + (Right(tblConvertNumber, 1) * 1)
            Else
                tblDecimalValue = (tblDecimalValue) + (Right(tblConvertNumber, 1) * (2 ^ (W - 1)))
            End If
            tblConvertNumber = Left(tblConvertNumber, Len(tblConvertNumber) - 1)
        Next W
        
        If tblDecimalValue > WorkerFactorDecimal Then
            With rs
            .Edit
            !ActivityStatus = "n"
            .Update
            End With
        Else
            InterimChoiceBoolean = Len(ChoiceBoolean) - 1
            For z = 1 To Len(ChoiceBoolean)
                If Showit <> "" Then Exit For
                ' Set Variables
                NumtoRemove = Len(WorkerFactorBoolean) + 1 - z
                
                InterimChoiceBoolean = Mid(ChoiceBoolean, NumtoRemove, i)
                InterimtblBoolean = Mid(tblboolean, NumtoRemove, i)
                OneInInterimtblBoolean = InStr(InterimtblBoolean, "1")
                
                If InterimChoiceBoolean = InterimtblBoolean And OneInInterimtblBoolean >= 1 Then
                    With rs
                    .Edit
                    !ActivityStatus = "x"
                    .Update
                    End With
                    Exit For
                End If
            Next z
        End If
    rs.MoveNext
    Loop
Next i
DoCmd.SetWarnings True
Screen.ActiveForm.Refresh
rs.Close
End Sub
                                              
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by: noclewPosted on 2009-11-13 at 05:55:49ID: 25813845

GRayL:

After more vigorous testing, the above does not quite work.  I'm still interested in what you may come up with.

 

by: GRayLPosted on 2009-11-13 at 08:16:40ID: 25815145

I've had my share of snags too - still at it.

 

by: noclewPosted on 2009-11-13 at 09:46:07ID: 25815985

Alright.  I believe i've got it now.  tested it up to 16 places and it seems to function correctly with any cominbation.  I'm going to keep expanding the test and see how high I can go.  Have a look and tell me what you think...

Public Sub TableResults()
Dim rs As DAO.Recordset
Dim tblBoolean, NumberofOnes, tblOneLocation, Showit
 
' Set statements
Set rs = DBEngine(0)(0).OpenRecordset("tblActivities")
 
' Reset all ActivityStatus values to ""
rs.MoveFirst
Do While Not rs.EOF
    With rs
    .Edit
    !ActivityStatus = ""
    .Update
    End With
rs.MoveNext
Loop
rs.MoveFirst
 
Do While Not rs.EOF
    ' Set Variables
    tblBoolean = rs!ActivityShowBoolean
    Showit = rs!ActivityStatus
        
    ' Count the Number of ones in the tblrecord
    NumberofOnes = 0
    For i = 1 To Len(tblBoolean)
        If Mid(tblBoolean, i, 1) = "1" Then NumberofOnes = NumberofOnes + 1
    Next i
        
    If NumberofOnes > 0 And Showit = "" Then
        tblOneLocation = 0
        For i = 1 To NumberofOnes
            tblOneLocation = InStr(tblOneLocation + 1, tblBoolean, "1")
            If Mid(WorkerFactorBoolean, tblOneLocation, 1) = "0" Then
                Showit = "n"
            Else
                If Showit = "" Then Showit = "x"
            End If
        Next i
            With rs
            .Edit
            !ActivityStatus = Showit
            .Update
            End With
    End If
NextRecord:
rs.MoveNext
Loop
DoCmd.SetWarnings True
Screen.ActiveForm.Refresh
rs.Close
End Sub

                                              
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by: GRayLPosted on 2009-11-13 at 11:54:15ID: 25817150

Here's how - speeding up the creation of the query below may be desirable.  After many days of looking at this problem I conclude that if you eliminated all the possible binary numbers that contained a zero where your Boolean number had a zero, you would be there.  First I used Excel to create a list of all the binary numbers for decimal values 1 to 255 (eight digits, 255 different values using the Dec2Bin() Excel function.  I then imported the table into Access. Then with a binary test number "10101001" I eliminated all the BinValue rows which contained a comparable zero using this query - zeroes at locations 2,4,6 and 7):

SELECT * FROM tblBinaries WHERE Mid(BinValue,2,1)<>"0" AND Mid(BinValue,4,1)<>0 AND Mid(BinValue,6,1)<>"0" AND Mid(BinValue,7,1)<>"0"

It returned this dataset of 16 records:

BinValue
01010110
01010111
01011110
01011111
01110110
01110111
01111110
01111111
11010110
11010111
11011110
11011111
11110110
11110111
11111110
11111111

Close??



 

by: noclewPosted on 2009-11-13 at 12:39:19ID: 25817490

Hi GRayL.  Your solution is close, but it's limited to the largest boolean to decimal conversion that excel can do (16 bits in some cases).  I think I'm going to stick with the solution I posted as it's not limited.  I'll give you the points though as you pushed me through to get it done.

 

by: GRayLPosted on 2009-11-13 at 12:59:20ID: 25817655

Thanks, glad to help.  You could create a larger data set using a VBA UDF in Access to populate the table past the 65,535 row limit of Excel.  With autonumber Increment as a primary key m, you can get the binary equivalent of  m using a small table or array with fields n and two2n (meaning 2 to the nth power), finding largest two2n less than m, doing the difference, and doing the same for the difference until you get to zero.  Good luck with your project.

20120131-EE-VQP-002

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