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11/06/2009 at 09:59AM PST, ID: 24878750
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7.4

find a record in a recordset

Asked by TimTDP in Access Coding/Macros

Tags: Microsoft Access 2000

Using Access 2000, I need to find a record in a table.

I have create a DAO recordset and thought I could use the .find command

With rstData
    .MoveLast
    .MoveFirst
   
    Do Until .EOF
   
    .FindFirst "Serial Number*"
    RecordNumber = .Bookmark
End With

on the line of code .FindFirst "Serial Number*" I get a run time error 3077 " Syntax error (missing operator) in expression

The data in the table looks like this:

### RECEIVING FILE PROCESS STARTED ###
Receive Date: 02-Nov-09 08:37
File received through $_POST.
Uploading Company: Company Name
Uploader Version: 1.14
Filename: 8030019708.xls
File Length: 3660
Serial Number: 8030019708
Start Date: 09-10-2009-10-06-37
End Date: 02-11-2009-06-36-39
Unix Start Date: 1255075597
Unix End Date: 1257136599
Tag owner is : *******
Adding file to : ID 15749
File has been written to files.
### RECEIVING FILE PROCESS TOOK 327 MILLISECOND(S) ###

What is wrong with my code?
I need to move to the record containing "Serial Number: 8030019708"

Once I have found the serial number, I bookmark the record number. I will then move away from the record, but at a later stage I need to move back to it.
How do I move to a bookmark?

Thanks in advance
 
Keywords: find a record in a recordset
Title
1 VBA - Recordset Index
2 ADO Recordset from IP Address Bind t…
3 Bookmark on Sub Form
4 Doubt in ADO?
5 Setting RowCount
6 find method
 
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About this solution

Zone: Access Coding/Macros
Tags: Microsoft Access 2000
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Solution Provided By: TimTDP
Participating Experts: 4
Solution Grade: A
 
 
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