[x]
Posted via EE Mobile

Search, ask, and monitor your questions on the go with EE Mobile. Visit Experts Exchange from your mobile device and never be out of touch again.
Question
[x]
Attachment Details
[x]
The Solution Rating System

With so many solutions, how can you tell which solutions are most likely to help you and which ones are not? To provide you with a tool to use, we rate our solutions based on various elements that most accurately determine if a solution is a quality solution. To explain what factors affect the solution rating, here are the elements we take into consideration when formulating our solution rating.

  • The Grade of the Solution
  • The Zone Rank of the Expert Providing the Solution
  • The Number of Author and Expert Comments
  • The Number of Experts Contributing
  • The Feedback of the Community

Your Input Matters
Because of the way the system is set up, the most important variable in this equation is you. As a member of Experts Exchange, you are able to cast your vote on the quality of the solutions in regard to how complete, accurate, helpful and easy to understand each solution is. When you provide your feedback, each rating is adjusted accordingly. So, if you see a solution that has a poor rating that you think is a good solution, let us know by rating it. As you do, the rating will be adjusted and will become more accurate for other members of our site.

If you have any suggestions that you would like to make for our rating system, please ask a question in the Suggestions Zone of Community Support.

Thank you!
9.6

Syntax for Left Join with query aliases in Access

Asked by billb1057 in Microsoft Access Database

Tags: Access, SQL syntax, Join, Left Join, alias

This question was helpful in showing how to create Joins.
http://www.experts-exchange.com/Databases/MS_Access/Q_20950529.html

I'm not sure I'm asking this correctly, but how would the syntax work with "alias queries" (I'm not sure if that's the right term)?  So, three queries on one table (as a, as b, as c) for example, then with a Left Outer on each one from a reference table.
The goal is to get All of the organizations (in the reference table) and any of the results in the queries by various criteria.  This is a survey -- so the reference table = "Operations".  The other table is "Surveys".

I tried something like

select a.OperName, b.CountS, c.CountD, d.CountN
From
(select OperName
from Operations) a,
(Select count(Category) As CountS
From Surveys
Where Category = "Satisfied") b,
(Select count(Category) As CountS
From Surveys
Where Category = "Dissatisfied") c,
(Select count(Category) As CountN
From Surveys) d
where a.OperName = b.OperName = c.OperName = d.OperName

But that doesn't work at all -- and it's not a Left Join ON ... b.OperName, etc.

putting that term in at the end doesn't work either.

Thanks in advance for your help.

1:
2:
3:
4:
5:
6:
7:
8:
9:
10:
11:
12:
13:
14:
15:
16:
17:
18:
19:
20:
21:

-- Reference table
 
Select Distinct OperName
From Operations
 
-- Satisfied Surveys
 
Select count(Category) As CountS
From Surveys
Where Category = "Satisfied"
 
-- Dissatisfied Surveys
 
Select count(Category) As CountS
From Surveys
Where Category = "Dissatisfied"
 
--- Sample Size
 
Select count(Category) As CountN
From Surveys
Related Solutions: JOIN, INNER JOIN, OUTER JOIN, RIGHT JOIN, LEFT JOIN
[+][-]07/13/09 02:45 PM, ID: 24844303Accepted Solution

View this solution now by starting your 30-day free trial. Setting up your free trial is quick, easy, and secure. We will return you to this solution, unlocked, when you're done.

About this solution

Zone: Microsoft Access Database
Tags: Access, SQL syntax, Join, Left Join, alias
Sign Up Now!
Solution Provided By: datAdrenaline
Participating Experts: 2
Solution Grade: A
 
[+][-]07/13/09 02:33 PM, ID: 24844216Assisted Solution

Assisted solutions are selected by the member who asked the question as a comment that contributed to their question's solution.

Start your 30-day free trial to view this Assisted Solution or ask the Experts your question.

 
[+][-]07/13/09 06:08 PM, ID: 24845528Author Comment

Often, when Experts are collaborating with members who have asked questions, they will request additional information about the problem. Askers respond with an author comment like this one.

Start your 30-day free trial to view this Author Comment or ask the Experts your question.

 
[+][-]07/13/09 06:17 PM, ID: 24845595Author Comment

Often, when Experts are collaborating with members who have asked questions, they will request additional information about the problem. Askers respond with an author comment like this one.

Start your 30-day free trial to view this Author Comment or ask the Experts your question.

 
 
Loading Advertisement...
20091118-EE-VQP-93 - Hierarchy / EE_QW_Related_20080208