Question

Why does FileDialog not work

Asked by: rkm0312

I have used this code before and it has worked fine, however, now I am getting an error "Method or data member not found".  I have a reference to the MS Office 12.0 Object Library.  I have also tried the 11.0 and the 10.0 object library.  It acts as if it is having trouble with .FileDialog.

Public Function SelectFolder() As String
'Requires Office XP (2002) or higher
'Requires a reference to the Microsoft Office Object Library
'Created by Helen Feddema 3-Aug-2009
'Last modified 3-Aug-2009
 
On Error GoTo ErrorHandler
 
   Dim strFolderPath As String
   Dim fd As Office.FileDialog
   
   'Create a FileDialog object as a Folder Picker dialog box.
   Set fd = Application.FileDialog(msoFileDialogFolderPicker)
   
   With fd
      .Title = "Browse for folder where Word templates are located"
      .ButtonName = "Select"
      .InitialView = msoFileDialogViewDetails
      '.InitialFileName = strPath
      If .Show = -1 Then
         strFolderPath = CStr(fd.SelectedItems.Item(1)) & "\"
      Else
         Debug.Print "User pressed Cancel"
         strFolderPath = ""
      End If
   End With
 
   SelectFolder = strFolderPath
   
ErrorHandlerExit:
   Exit Function
 
ErrorHandler:
   MsgBox "Error No: " & Err.Number & "; Description: " & Err.Description
   Resume ErrorHandlerExit
 
End Function

                                  
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Asked On
2009-10-19 at 08:01:20ID24823765
Tags

Access

,

VBA

Topic

Microsoft Access Database

Participating Experts
2
Points
500
Comments
10

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Answers

 

by: hnasrPosted on 2009-10-19 at 08:23:04ID: 25606003

Use fd.Show in proper place

 

by: rkm0312Posted on 2009-10-19 at 08:46:49ID: 25606292

I don't know what that means.  Where is the proper place?

 

by: hnasrPosted on 2009-10-19 at 10:27:10ID: 25607149

Sorry, ovelooked your statement If .Show = -1 Then
Your code is working fine with me.

It may be a references problem.

Attach your minimal database to check.

 

by: rkm0312Posted on 2009-10-19 at 12:02:06ID: 25607990

It was working for me at home and then I brought it to work and it failed. (Access 2007 at home 2000 at work - both XP systems). I assumed it was a reference issue, but I have tried all that I know.  I have attached my .mdb.  It is a very simple database.  The appliction is to allow the user to select a folder and the script will read appropiate text files, gather data and report the results.  There are other ways to get the folder information from the user, however the method that I used was working and was exactly what I needed and was familiar to my user.

  • forJacob.mdb
    • 352 KB

    gather data from text files (.gr, .ppi)

 

by: harfangPosted on 2009-10-19 at 12:59:27ID: 25608421

Try to comment out the line "On Error Goto". Provoke the error, and you should have the option to [Debug] your code. The missing method should be highlighted, and you can explore the problem, for example by using the Immediate Pane (trying out various commands directly while the code is still active). Perhaps you will discover that .ButtonName is the problem and not .Show...

I don't think it's a reference problem, or you would have a compile error on the declaration of fd, not a run-time error.

(°v°)

 

by: rkm0312Posted on 2009-10-19 at 13:21:13ID: 25608644

It does give me a compile error 'Method or member not found'.  It seems to fail on the - Set fd = Application.FileDialog(msoFileDialogFolderPicker) line and highlights the .FileDialog portion of the line.  As you can see the office object library is there - are there any other libraries that need to be referenced?  If I remove the office object library it does fail on the Dim fd As Office.FileDialog line.

 

by: harfangPosted on 2009-10-19 at 14:26:34ID: 25609210

No libraries are needed to use the Application object. If you type this in the Immediate Pane, does it work?

    Application.FileDialog(4).Show

If it doesn't, what version of Access are you using? This doesn't seem related to the Office library version...

(°v°)

 

by: rkm0312Posted on 2009-10-20 at 05:25:12ID: 25613262

No, it does not work.  I am using Access 2000.

 

by: rkm0312Posted on 2009-10-20 at 10:33:58ID: 25616471

It works in Access 2003, so I must assume that the problem is that I was trying to run it in Access 2000.  Thank you for your help

 

by: harfangPosted on 2009-10-20 at 12:22:55ID: 25617487

Yes, Access 2000 doesn't implement the file dialogs. There are solutions for Access 2000, using WinAPI calls. Do you need pointers for that?

In any case, thanks and success with your project!
(°v°)

20120131-EE-VQP-002

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