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06.23.2008 at 12:46PM PDT, ID: 23508838
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9.9

Fetch Next From Cursor 2 values into 2 variables

Asked by wsturdev in SQL Query Syntax

Tags: , ,

I am trying to create a UDF.  My code is attached.

For each row retrieved by the SELECT statement there will be 2 values.  

What is the corret syntax to access both retrieved values?  What should I use instead of:
            FETCH NEXT FROM BusinessCommentCursor
            INTO @Business_Comment, @Employee_Name
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ALTER FUNCTION [dbo].[Assemble_Business_Comments]
	(@Apps_Cat_ID int)
	RETURNS varchar(8000)
	AS
	BEGIN
		DECLARE @Employee_Name varchar(100)
		DECLARE @Business_Comment varchar(8000)
		DECLARE @Business_Comments varchar(8000)
		DECLARE BusinessCommentCursor CURSOR READ_ONLY FOR
		SELECT Tbl_Survey_Business_Respondents.Respondent_Comment, Tbl_Client_Employees.Employee_Name
			FROM Tbl_Survey_Business_Respondents INNER JOIN
                      Tbl_Client_Employees ON 
                      Tbl_Survey_Business_Respondents.Lookup_To_Tbl_Client_Employees_For_Business_Respondent = Tbl_Client_Employees.ID
			WHERE (Tbl_Survey_Business_Respondents.Apps_Cat_ID = @Apps_Cat_ID)
		OPEN BusinessCommentCursor
 
		FETCH NEXT FROM BusinessCommentCursor
		INTO @Business_Comment, @Employee_Name
 
		WHILE @@FETCH_STATUS = 0
		BEGIN
			IF @Business_Comment is not null 
				SET @Business_Comments = @Business_Comments + CHAR(13) + CHAR(10) + CHAR(13) + CHAR(10) + @Employee_Name
				SET @Business_Comments = @Business_Comments + CHAR(13) + CHAR(10) + @Business_Comment
			FETCH NEXT FROM BusinessCommentCursor
			INTO @Business_Comment, @Employee_Name
		END
		CLOSE BusinessCommentCursor
		DEALLOCATE BusinessCommentCursor
		IF @Business_Comment is null
			SET @Business_Comments = N'None provided'
      RETURN (@Business_Comments)
	END
 
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[+][-]06.23.2008 at 12:54PM PDT, ID: 21849702

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[+][-]06.23.2008 at 01:00PM PDT, ID: 21849756

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[+][-]06.23.2008 at 01:02PM PDT, ID: 21849774

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[+][-]06.23.2008 at 01:05PM PDT, ID: 21849801

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About this solution

Zone: SQL Query Syntax
Tags: User Defined Function, SQL 2005, syntax
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Solution Provided By: angelIII
Participating Experts: 1
Solution Grade: A
 
 
 
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