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-What's the size of a photon
-What happens to it when it is 'absorbed' by a surface (like an opaque surface)
-What's the mass of a photon
That's what I can think of right now..
Thanks
:-)
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If you restrict the 'size' of a photon by puting it in a box or squeezing it through a hole,
you create uncertainty in its momentum.
By one measure, they are very small, as two beams of photons can cross and there are very very few interactions.
By another measure, if you put one photon through a device that can measure its momentum very accurately, then its position uncertainty, and therefore its extent, is very large.






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If size is defined as its physical extent, the answer is simple, it's just
(h bar)/(2*momentum uncertainty)
Which can be very small if you put the photon in a very small box, or very large if you measure its momentum very accurately (using a very large box)
Righto, but most of us (with a classical view of things) have the intuition that if two things pass by each other without (classically) hitting, they've not intruded on each other's (classical) extent.

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I thought it must have a size, since I can see light through a hole in the wall, but not through a wall.. But I'm always overseeing laws of physics..
For the mass, does it mean that there are different masses in photons, depending on its wavelength? I would like some concensus if possible.. I've been trying to understand photons forever..
And why do they bounce anyway? Are they elastic? How come they don't just crash into surfaces like most other particles would? Or just go through, like most waves?
I need a brain..
:-)
However for small particles this principle becomes very important.
As a collateral effect of this principle, for extremely fast objects (eg. photons) this means that the uncertainity on their position (and their size) becomes huge.
By the way, photons have a dual caracter. At the one hand they behave as particles, at the other as waves. So it the hole in your wall is small enough (in the order of magnitude of the wavelength) other fenomena such as diffraction occur.
Reflection on metals is due to the fact that the electrons in metals are not really bound to a specific atom. This makes that there are a lot of different energy levels available. The electron goes immediately to an other energy band (in metals we speek about energy bands and not about orbitals) and immediately fall back.
Hopes this helps
Right. Down to physical measurement, it indicates that even the most accurate measuring device will alter, even slightly, the object measured, generating therefore innacurate results. For instance, when you use the ruler to know the length of a sheet of paper, the weight of the ruler will expand the surface of the paper, altering the length you wanted to measure. Same happens when you want to know the lbs of a tyre. You let some air go, and thus the lbs you obtained are not equal to those existing prior to your measurement. Even when you look at something, the object is altered, in the smallest detail, by the photons which hit the object and reflect to your eyes.
That is why some people consider that the conclussion of Heisenbergh's principle of uncertainty is that the truth is impossible to reach, scientifically proving Gorgias' (an ancient greek nihilist philosopher) statement that "nothing exists, if anything does exist it cannot be known, if anything exists and can be known, it cannot be communicated".
Brgds.,
germanpenn






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It will be difficult to see light through a hole smaller than the wavelength of the photon.
>> For the mass, does it mean that there are different masses in photons
All photons have zero 'rest mass', which is what the word 'mass' generally means to physicists.
Photons have a 'relativistic mass', which is an outdated term meaning 'energy', that is proportional to its frequency (Planck's constant times the frequency)
>> And why do they bounce anyway?
They don't really bounce, they are absorbed and re-emited.
It has no defined size
-What happens to it when it is 'absorbed' by a surface (like an opaque surface)?
Its energy usually show up as heat
-What's the mass of a photon?
It has no rest mass
Actually, with less energy it would tend to be larger.

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With a lot of energy: Very concentrated Gauss bell. Portion above 0.1 is small (radius)
^
/ \
/ \
-- --
With less energy: Gauss bell very dispersed. Portion obove 0.1 wider but not as high.
___----¨¨¨¨¨¨----____
__---¨¨ ¨¨---___
Hope the graphs display OK in everyone's screen and font!






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That may be misleading, so perhaps I should try to clarify.
Total momemtum is proportional to total energy, but momentum las components in different directions, each of which can have its own uncertainty, so the extent of the photon can be different in different directions.
You might squeeze a photon through a hole in a wall, restricting its x,z extent,
and causing uncertainty in its x,z momentum, but it may still have a large y extent,
with less uncertainty in its y momentum.
Visible light can go through glass because the electons in the glass are too tightly bound to be easily shaken loose by the photons, so the light travels through without much interaction.
Nope - the resonating frequencies of glass-electrons (to shift them in higher energy levels) doesn't match the frequencies of visible light
take water - light goes through water, microwaves not (they boil the water) .. but microwaves are just same "light"-waves with a different frequency that matches the water.. so the "strong" boundage couldn't be the issue
Micowaves do not match the resonant frequencys of water. The water molecules heat up because they rotate in response to the changing E fields.

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I heard that somewhere they can send ONE photon (fiber optics??) at the time.. That sounds to me that a photon is a unit (as opposed to a wave; we can't send ONE radio wave, can we?)
I'm still cracking my head here, all this input is great!
:-)
holger
There's experiments that only make sense if photons are particles (like the photoelectric effect-- electons are knocked out of metals in milliseconds, even if the light intensity is waay too weak to send that amount of energy in a century).
Other experiments only make sense for waves (interference-- how could a single photon interfere with itself?)
Very peculiar stuff. I think about it on my commute. I'm surprised I havent rear-ended another car while pondering this stuff.






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That's only, because you were diffracted from both sides of the car in front, and your particles met each other again undestryed ;-))
Lambda = c/f "
"E = m c ^ 2
and solving for m : m = E / c ^2, you can calculate the mass. (in kg per photon)
Suppose a photon has an energy of 1 * 10 ^ -19 Joules (somewhere in the visible light). The corresponding mass is then :
1*10^ -19 * (3 * 10 ^5) ^ 2 =
9 * 10 ^ - 9 kg"
The above statements are telling me that a photon has a mass and a size: are those statements accurate?
:-)
If by "mass" you mean the current usage of the word, which is equivalent to the old term "rest mass", then no.
If by "size" you mean a hole which it is difficult for it to fit through, then yes.

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something like:
If you have two electrons A and B, you can say there is a certain diistance between them,
but you can't say A is two furlongs west of B, because electrons are indistinguishable from one another.
The idea being if you arent staring at each one, they could swap places on you.
I can agree with your statement of the mass.
However for the size things are a bit more complicated. You correctly calculate the wavelength as a function of the frequency and so wavelength could definitively be related to the size.
However the wavelength is not the size. There are some problems : How many periods of this wave is one photon? What about diffraction ? ...
Also take in minf that uptill now everything has assumed the photn in a vacuum. However, if we are not in a vacuum the frequency remains the same but c diminishes, so lamba becomes also smaller ...
Hopes this helps
:-)






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What do you mean by particles smaller than photons?
An electron has no measurable "size" (although classically it might be said to have a radius between 3*10^-15m and 3*10-18m)
But most of the photons we see were emited from electrons on the surfaces of objects.
I figure that, if my soccer ball is the photon, I can never see a tennis ball..
:-)
(3*10-18m should have been 3*10^-19m)
You can get photons to create a pattern of electrons, off which you can bounce other photons to see the pattern.

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what's the color of a photon? Is there anything that we can call 'natural state' of a photon(before it bounced off anything at all?)
Thanks for all the patience..
:-)
Thanks all!
:-)






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Although in the vitreous humour the wavelength would be shorter.
It may be better to describe the frequency,
384THz red to 769THz violet.
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