225.225.224.0
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Browse All TopicsHello,
I would like to link my network to the one next door. Currently, he has the address range 192.168.30.1-254 and I have the address range 192.168.0.1-254.
What subnet mask would we need to use to allow these two networks to "talk" to each other? I have tried reading up on subnets but I am struggling to understand it.
Thanks,
Jonathan
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network portion of ip addresses must be the same. This addresses are class C, then the first three octets must be the same. The better way is to add second IP address to you NIC, which is in the network of your neighbor, or ask your friend to migrate to 192.168.0.0 network or you can migrate yours to 192.168.30.0. You can use Lan calculator from this page (http://lantricks.com/down
To 'talk' each other the different networks, traffic between them must be flow trough a gateway router, server.
Thank you for your replies. So, for what you have said, I can either do the following-
Put a router in-between the networks to route the traffic - I would not know how to configure this though.
Add a second IP address
Change them all to use 192.168.0.x or 1092.168.0.30
Change them to use 255.255.224.0 as a subnet mask.
From what I understand, 255.255.224.0 is a class B subnet mask. If I changed the subnet to this but kept the same class C IP addresses, would there be any downside?
(I don't know if it makes a difference but we actually have a server in-between the two networks with a wireless connection to my network and a wired connection to my friends network, these two connections have then been bridged on the server.)
Don't worry about classes - we now have CIDR (and, if you insist. it's still class C anyway, as the above mask constructs 32 class C networks containing 8192 addresses each).
Please read this -
http://en.wikipedia.org/w
You'll
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by: PeteLongPosted on 2009-05-04 at 03:12:10ID: 24293675
Hello acsell,
These are both Class C, networks (have a 255.255.255.0 subnet mask) to make then "SEE" Each other you would need a router between the networks with a route to each network
Regards,
PeteLong