Hi. I hope this is the proper forum for a batch job question.
This is being run on Windows 2000 / XP machines. My batch job takes a series of files, and renames them with a date stamp on the end. For example, on 01/17/2006, a file might be renamed from PRFILEDS.EOS.IM to PRFILEDS.EOS.IM.01162006. On 02/04/2006, it would be renamed to PRFILEDS.EOS.IM.0232006. This secondary renaming is buggy, but acceptable as it still gets the point of the date across.
Now the problem: This batch job returns a two digit month, a two digit day, and a four digit year. So far, so good. That is, until you run this puppy on the 8th or the 9th of the month, then the "octal representation feature" of the SET command bites you *real* good. Here's the line that's causing the mayhem:
set %%G=%1&set /a %%H=%2-1&set %%I=%3
returns (on 03/08/2006):
set mm=03
set /a dd=08-1
set yy=2006
Which, because DOS treats a two-digit number preceded by 0 as an octal digit, causes the second SET to fail, producing:
set mm=03
set dd=
set yy=2006
How do I extract the right-hand digit from dd= when it's less than 10? Or is there a way around the octal issue? Any ideas?
Thanks in advance for any help you might provide.
Jay
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If you want dd to be 2 digits, you can also add "if %dd% lss 10 set dd=0%dd%"
rem Check the first digit of dd, if it is 0, then set dd to only the 2nd digit
if {%dd:~,1%}=={0} set dd=%dd:~1%
rem Convert dd to a number and subtract 1
set /a dd-=1
rem If dd is only 1 digit, pad with a 0
if %dd% lss 10 set dd=0%dd%
GuruGary and K_2K,
Thank you both for your solutions. I split the points based on what I learned more so than the value of the solution. I hope this does not offend either of you.
Both solutions are acceptable and produce the desired end result. GuruGary's answer (to me, at least) is more instructive. K_2K's is lean, mean, and just plain sneaky. :) I had a serious "Doh!" moment when I saw that trick!
Again, thank you both very much for your assistance! And if you feel that the split wasn't fair, I'm more than willing to discuss a more equitable distribution of points.
Regards,
Jay
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Answer for Membership
by: GuruGaryPosted on 2006-03-08 at 15:49:29ID: 16140113
If I understand correctly, you want want to fix the dd value if it is less than 10. Try something like this:
rem Check the first digit of dd, if it is 0, then set dd to only the 2nd digit
if {%dd:~,1%}=={0} set dd=%dd:~1%
rem Convert dd to a numerical value
set /a dd=%dd%
rem Subtract 1 from dd
set /a dd-=1