That is SO, SO, SO unusual.... I don't think it would ever have occurred to me to enclose the expression in quotes...
Thank you
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Question
Nested IF statements
Due to serious lack of sleep I am having difficulties concentrating on the following:
The problem is this. The simple condiional statements work well on their own however, when the conditional statements are combined the code produces an error.
I am not concerned with the mathematical formulas.
For the curious though, the code simply generates a year-value. If no parameters are passed then it generates a random date between 1752 to the current year. If parameters are passed then it generates a random year-value between %1 and %2. If only one parameter is passed then a year-value is not generated.
CODE 1 (Works okay)
@echo off
if "%1"=="" set /a RndYear = %random% %% (%date:~6,4% - 1752 + 1) + 1752
if not "%1"=="" if "%2"=="" exit /b
if not "%1"=="" set /a RndYear = %random% %% (%2 - %1 + 1) + %1
exit /b %RndYear%
CODE 2 (Same code using nested IFs - does not work)
@echo off
if "%1"=="" (
set /a RndYear = %random% %% (%date:~6,4% - 1752 + 1) + 1752
) else (
if "%2"=="" (
exit /b
) else (
if not "%1"=="" set /a RndYear = %random% %% (%2 - %1 + 1) + %1
)
)
exit /b %RndYear%
I have tried negating the conditions however, I receive the same error.
This may be a simple problem as it may be due to something I have overlooked. As I said, I'm dog-tired and mentally drained.
I have deliberately not included the error message because glancing at the code, both appear to be logically and lexically correct. My XP DOS version is 5.1.2600.
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by: MMierzwaPosted on 2009-04-28 at 00:41:38ID: 24248387
It seems that problem is in set not with if.
Try to put it in " ".
set /a RndYear = "%random% %% (%date:~6,4% - 1752 + 1) + 1752"
Should work.