Have loop issue:
set uLimit=5
for /L %%i in (1,1,%uLimit% ) do @echo %%i
I expect the following results:
1
2
3
4
5
But I syntax error. Is it possible to be done?
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That should run just fine as batch script.
If you're entering this in a shell directly, you need to drop one of the percent signs for the loop variable:
set uLimit=5
for /L %i in (1,1,%uLimit% ) do @echo %i
If it's not running as a batch script, make sure you're using cmd.exe (32bit NT Shell), NOT command.com (16bit DOS).
You had a few extra spaces although it didn't throw up an error with me.
set uLimit=5
for /L %%i in (1,1,%uLimit%) do @echo %%i
If you intend using an intermediate variable then you're gonna have to use delayed expansion and use !..! instead of %..%. See below:
setlocal enabledelayedexpansion
set uLimit=5
for /L %%i in (1,1,%uLimit%) do (
set count=%%i
echo !count!
)
Here's another example - it displays the 5-times table:
setlocal enabledelayedexpansion
set uLimit=5
for /L %%i in (1,1,%uLimit%) do (
set /a product=%%i * 5
echo !product!
)
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by: milindsmPosted on 2009-11-05 at 23:13:31ID: 25757215
@echo off
SET cnt=0
Goto loop
:loop
SET /a cnt = cnt +1
IF %cnt% == 6 goto :eof
echo %cnt%
goto loop