Question

einstine v/s newton

Asked by: shreshthwadhwa

let us assume classical physics
"time is independent of the observer"
then if we keep a rod in front of us we will see its ACTUAL length

now acording to einsines special theoy of relativity
"time is dependent on the observer"
so if we keep a rod in front of us then we will NOT see the ACTUAL length of the rod ?

/?WHY IS IT SO??
?????

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Asked On
2008-05-28 at 02:37:03ID23437448
Topics

Math & Science

,

Puzzles & Riddles

,

Miscellaneous

Participating Experts
6
Points
50
Comments
11

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Answers

 

by: ozoPosted on 2008-05-28 at 02:53:53ID: 21658943

What do you mean by "actual" length?

Just as directions in space are relative, so that one person's "breadth" may look like another persons "depth", directions in space-time are relative so that what one person measures as space, another person measures as time.
Moving at a velocity relative to another mixes up the time and space directions of two different frames in a way analogous to how facing a different direction can mix up the
front-back coordinates of one person with the left-right coordinates of another.

 

by: grg99Posted on 2008-05-28 at 04:57:22ID: 21659553

As long as you and the rod are either "stationary" or traveling at the same speed in the same direction,  the rod will look "normal".

It's when you and the rod are travelling at different speeds, then the rod will look funny.

And a "stationary" observer  will see both of you distorted.

 

by: shreshthwadhwaPosted on 2008-05-28 at 05:44:26ID: 21659827

what do u mean by
what one person measures as space, another person measures as time.
measuing space???????????
well my Q is if there is a rod of 5 meter (in 1D)(rod is stationary)
if we look through einstines special theory of relativity then is length will not be ==5 meter
"because time is dependent on observer"
but according to newton time will be independent of position of observer
then length == 5 meter

 

by: SyntheticsPosted on 2008-05-28 at 06:29:37ID: 21660160

Time and space only get confused in relative motion. If relative motion is 0, the rod appears to be its "true" length in both einsteinian and newtonian models. If relative motion != 0, only the newtonian model will predict it to appear its "true" length, because time and space get slightly mixed up.

I heard it said once that the time dimension is rotated into the physical three. Not sure I understood that though.

 

by: aburrPosted on 2008-05-28 at 09:44:15ID: 21662028

"well my Q is if there is a rod of 5 meter (in 1D)(rod is stationary)
if we look through einstines special theory of relativity then is length will not be ==5 meter
"because time is dependent on observer"
but according to newton time will be independent of position of observer
then length == 5 meter"

The simple answer if that if the rod is stationary (with respect to the measurer) the rod will measure 5 meters to BOTH Einstein and Newton.

When considering special relativity one  must make distinctions between "appears" and "measure" between "is" and "measured". One must distinguish between "relative" and "absolute". All the unusual aspects of the special theory cannot be cleared up here.  Read a good book on Special Relativity. A good, clear, elementary book is "Spacetime Physics" by Taylor and Wheeler

 

by: ozoPosted on 2008-05-28 at 10:42:46ID: 21662532

 

by: ozoPosted on 2008-05-28 at 12:50:07ID: 21663701

two events, say, at either end of a rod, may appear to one person to be separated by 13 meters in space, and 12 (meters/C) in time
those same events may appear to another person to be separated by 5 meters in space and 0 (meters/C) in time.

sort of like one person might think two positions in space a are separates by 12 steps forward and 5 steps to the left, and another might think they were separated by 13 steps to the right.

 

by: shreshthwadhwaPosted on 2008-05-29 at 09:56:33ID: 21671000

in a bit simpler way please!

 

by: dragonjimPosted on 2008-05-29 at 14:44:47ID: 21673568

Not sure if this will be of any help (as primer to space-time): http://www.theory.caltech.edu/people/patricia/st101.html

 

by: aburrPosted on 2008-05-29 at 15:54:34ID: 21674003

There is nothing simpler than
-
The simple answer if that if the rod is stationary (with respect to the measurer) the rod will measure 5 meters to BOTH Einstein and Newton.

 

by: SunBowPosted on 2008-06-11 at 20:47:57ID: 21766082

> /?WHY

<snore><um> Hey what's up. What rod? Where? <zzzzzzzzz>

[time is relative][seeing is relative]

20120131-EE-VQP-002

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