The angle is the arctan( 9/12) = 36.8 degrees.
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Browse All TopicsI need to cover an area with a tarp, but sloping downward to allow rain to run off.
The area to be covered is 12 feet long (ground/linear measurement).
The tarp will start 9 feet above the ground and slope downward at roughly a 25 degree angle.
How much length of tarp will I need to cover the 12 linear feet after adjusting for the slope?
|*tarp starts here, 9 feet up
|**angled down at ~25 degrees
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Would be great if you could include the formula too :-) .
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But I dont want the tarp to come down to the ground ... only as far down as it would go at roughly 22-25 degrees.
So it won't form a triangle -- it will be an open-ended rectangle.
That is, where the tarp ends up after sloping down should still be some feet off the ground, not at ground level.
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| |--<<-- tarp ends here
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I can tie the tarp to the middle of the pole, it doesn't hv to reach all the way to the ground.
Oops, you are quite right as to the COS().
However, I still think the overall formula and result are wrong.
The side being determined is the hypotenuse. If one side is 12 ft and the other is 3.34 ft, the hypotenuse should be sqrt(12^^^^2 + 3.34^^^^2) which is 12.46 (even I know sqrt of (a^2 + b^2) :-) ).
I can't find any calculation that yields a tarp length of over 13 ft with a linear distance of 12 ft and an angle less than or equal to 25 degrees.
Perhaps you can correct me:
linear distance (12 ft)
--------------------------
---<<--25 degree angle
--tarp
--------extending
-------------------at 25 degrees
--------------------------
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by: d-glitchPosted on 2008-06-19 at 08:46:51ID: 21823394
You need at least sqrt(9² + 12²) = sqrt(225) = 15 feet.
A little more to allow for some sag.