Question

How to approach this problem?

Asked by: mamnoun77

An object at rest on a flat, horizontal surface explodes into two fragments, one seven times as massive as the other. The heavier fragment slides 5.60 m before stopping. How far does the lighter fragment slide? Assume that both fragments have the same coefficient of kinetic friction.

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Asked On
2009-11-05 at 13:35:37ID24876194
Tags

Physics

Topic

Math & Science

Participating Experts
3
Points
500
Comments
4

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Answers

 

by: PaulHewsPosted on 2009-11-05 at 14:26:48ID: 25754783

Explosion into two parts: You can use conservation of momentum to find unknown velocity for given mass.  But you don't have any *known* velocity for the 7mass.

What you do know is that 7mass does work (that you can calculate) against the opposing force of friction... Work back from that to find initial velocity since that kinetic energy is transformed into work...  That should suggest what you have to do in the other direction.

 

by: d-glitchPosted on 2009-11-06 at 06:04:35ID: 25759145

Assign values to make the problem more specific.

Suppose you have two oversize hockey pucks:  one is lead (7 kg)  the other is aluminum (1 kg).
They both have Teflon bottoms (or sandpaper or something in between), so the coefficient of friction is the same.
They have springs on their rims.

You push them together, compressing the springs, and let them go.

The heavy one has an initial velocity of 1 ms (this is arbitrary), and comes to rest 5.60 meters away.

In this case, you should be able to find everything:  the initial momentum, velocity, energy, and distance traveled
of both pucks, and the coefficient of friction.

 

by: aburrPosted on 2009-11-06 at 17:08:56ID: 25764468

Work done on heavier mass leads to its KE which leads to its velocity which leads to the velocity of the lighter mass which leads to the KE of the lighter mass which leads to the distance it travels.
If you need the equations to replace the "leads to", ask.
Is this home work? If so, do you want or need more explanation of the physics behind the steps? If so ask.
If not, the specific equations can be forthcoming.

 

by: mamnoun77Posted on 2009-12-06 at 01:18:04ID: 31650757

got the idea

20120131-EE-VQP-002

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