Got the instructions already: it's the "two for the price of one" that's the difficult part. I suppose the 5 letter groupings make it more challenging to crack.
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Crypto challenge 13: T T C E W R H I E N O O E R O O F P F
S H C N S O E E F E C H K A M P I T O E O O E E R O T D H A
P E G O T N L I U M H E S W T I T E T H E G S U T U N I E A
O F H D I U T I E B W R O O L H T C S I I N G T P I S L H M
H R A A Y R E H N P T E S G N L T X M O T S T H I T F O T W
B M E U T E H R E O D I U H S N E L S A L E A C A G O H V S
D O T I F L Y S E E O E W N A A E S B T T S O T E N S V T E
T S P T L T G E A O T M S E I A N T A I G T R E O S F W U I
L P H P F C P S R L E T O I T C A L W H H A E N F T W L T O
B U U T H T E I E E O R S E S I I N A P O B L T I I A V H N
1) J R R Y R T V L E L S V C P K Y N R U R Y K W R Y Y H I Q Y
K G V C T F K H E R A C F V C P K S E Q I K P V S S V N A Y
E D A Q L E
2) E S B H S G C C I X C B C J D R S P T K A D N B H T S W E I
K B R Y I I N J N I S H S N B I J T K A V K W E I
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Answers
Well, at least one person has figured out that the title and instructions are a railfence cipher. There are no clues in the title and instructions as to the contents of the two ciphers, apart from the cipher type, which you can probably guess from the length of the text and the frequency distribution anyway.
RobinD,
I used Wilhelm M. Plotz's CipherClerk's applet ( http://members.aon.at/ciph
OK, we'll start with the obvious clues for the ciphers. The two messages are monoalphabetic substitutions. They have different, loosely related, keys. If there is no progress on them by tomorrow, then I'll repost them with the correct spacing, as I think the five letter groups are hiding a lot of information.
RobinD,
It is a tricky one to decode. A four rail cipher would result in the 1st, 7th, 13th, 19th, ... character appearing in the top rail. Similarly the 4th, 10th, 16th, ... characters go to the bottom rail. The message is 270 characters long, so you can work out that the top rail ends at the 265th character from the plaintext and contains 45 characters. Similarly, the bottom rail ends at the 268th character and also contains 45 characters. The remaining 180 characters are divided equally betwen the two middle rails, which must each contain 90 characters. So split the message into strings of 45, 90, 90 and 45 characters, then space them out so you get the zig zag path and read the plain text.
..and finally...
1) ZOOLOGISTS FIND ALCOHOL A JOLLY RELAXING WAY TO UNWIND AFTER A DIFFICULT QUEST ..........sounds like a good idea :)
Real tough one, KelvinY! I thought this one would be 'cake' after reading in the instructions it was a monoalphabetic substitution. The j's q's z's and x's made it especially challenging. Your word seperations clue definitely helped.
On to the next one!
Great work, maramom. This week's ciphers were monoalphabetic substitutions, with tricky frequency profiles.
The full messages were
Crypto challenge 13: Two for the price of one
Since the last challenge was such a tough one, I have eased off on the difficulty this week. Below are two monoalphabetic substitutions. To get the points solve them, either separately, or together, and post the messages in plaintext. I am going to start the points off low, but I will bump them up if the ciphers are solved without hints.
1) ZOOLOGISTS FIND ALCOHOL A JOLLY RELAXING WAY TO UNWIND AFTER A DIFFICULT QUEST
2) KANGAROOS DO NOT PLAY JUMPING JACKS UNLESS IT IS AGAINST JUMBUCKS
The keys were 1) CROCODILE (offset to K) and 2) HUNTER (offset to S). The full encoding schemes were:
1)
ABCDEFGHIJKLMNOPQRSTUVWXYZ
KMNPQSTUVWXYZCRODILEABFGHJ
2)
ABCDEFGHIJKLMNOPQRSTUVWXYZ
SVWXYZHUNTERABCDFGIJKLMOPQ
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by: KelvinYPosted on 2006-10-16 at 08:52:52ID: 17739881
Hmm. I didn't think this one would last for so long without a nibble. Time for a clue I guess. Frequency analysis of the title and instructions should give you something close to plain English, implying that some kind of transposition has been used. More details on exactly which transposition was used if no more activity occurs in the next 24 hours.