NeverMind..I got the answer to my question myself..[:)]..!
Main Topics
Browse All TopicsI want to find the number of valid states in the problem of "Three Jealous Husbands" which is the famous River Crossing Problem.
This question is in progress.
Our experts are working on an answer right now.
Sign up for immediate access to the solution once it becomes available.
Experts Exchange has been collecting answers to technology questions since 1996…3 million and counting! If you have a question, chances are we already have your answer.
If you can't find the exact answer you're looking for, ask our exclusive community of 50,000 experts. You’ll get a personalized answer from a trusted professional.
Thousands of free tech tips, tricks, how-to’s and tutorials are available in our peer reviewed articles section. See for yourself how smart our experts are, no login required.
Access the answers to your technology questions today.
30-day free trial. Register in 60 seconds.
Members of the expert community talk about why the experience at Experts Exchange is different than what you will find anywhere else.

Try it out and discover for yourself.
30-day free trial. Register in 60 seconds.
Join the community of experts here and help other tech pros by answering question in your area of expertise. You can earn FREE access to all Experts Exchange's premium features and resources.
Wowww......
THANKS A LOT....!!
I GOT A WAY TO RECHECK...!!
I am glad... you replied..!!
Highly appreciated.
Maybe you meant possible states at any one location, not counting the rule that that no woman can be in the presence of another man unless her husband is also present.
which would be (64) combinations
But it that's what you meant, then you already know that the number of such states is 64
so I may be confused what you are asking.
I listed states that are valid under the constraint that no woman can be in the presence of another man unless her husband is also present, where state includes people on each shore and in the boat
6C6 = 1 (Cases having all 6 chars)
6C5 = 6 (Cases having 5 chars)
6C4 = 15 (Cases having 4 chars)
6C3 = 20 (Cases having 3 chars)
6C2 = 15 (Cases having 2 chars)
6C1 = 6 (Cases having 1 chars)
6C0 = 1 (Cases having 0 chars)
Tot = 64
A a B b C c Len Res
1 1 1 1 1 1 6 AaBbCc
1 1 1 1 1 0 5 AaBbC
1 1 1 1 0 1 5 AaBbc
1 1 1 0 1 1 5 AaBCc
1 1 0 1 1 1 5 AabCc
1 0 1 1 1 1 5 ABbCc
0 1 1 1 1 1 5 aBbCc
1 1 1 1 0 0 4 AaBb
1 1 1 0 1 0 4 AaBC
1 1 1 0 0 1 4 AaBc
1 1 0 1 1 0 4 AabC
1 1 0 1 0 1 4 Aabc
1 1 0 0 1 1 4 AaCc
1 0 1 1 1 0 4 ABbC
1 0 1 1 0 1 4 ABbc
0 1 1 1 1 0 4 aBbC
0 1 1 1 0 1 4 aBbc
1 0 1 0 1 1 4 ABCc
1 0 0 1 1 1 4 AbCc
0 1 1 0 1 1 4 aBCc
0 1 0 1 1 1 4 abCc
0 0 1 1 1 1 4 BbCc
1 1 1 0 0 0 3 AaB
1 1 0 1 0 0 3 Aab
1 1 0 0 1 0 3 AaC
1 1 0 0 0 1 3 Aac
1 0 1 1 0 0 3 ABb
0 1 1 1 0 0 3 aBb
1 0 1 0 1 0 3 ABC
1 0 1 0 0 1 3 ABc
1 0 0 1 1 0 3 AbC
1 0 0 1 0 1 3 Abc
0 1 1 0 1 0 3 aBC
0 1 1 0 0 1 3 aBc
0 1 0 1 1 0 3 abC
0 1 0 1 0 1 3 abc
1 0 0 0 1 1 3 ACc
0 1 0 0 1 1 3 aCc
0 0 1 1 1 0 3 BbC
0 0 1 1 0 1 3 Bbc
0 0 1 0 1 1 3 BCc
0 0 0 1 1 1 3 bCc
1 1 0 0 0 0 2 Aa
1 0 1 0 0 0 2 AB
1 0 0 1 0 0 2 Ab
0 1 1 0 0 0 2 aB
0 1 0 1 0 0 2 ab
1 0 0 0 1 0 2 AC
1 0 0 0 0 1 2 Ac
0 1 0 0 1 0 2 aC
0 1 0 0 0 1 2 ac
0 0 1 1 0 0 2 Bb
0 0 1 0 1 0 2 BC
0 0 1 0 0 1 2 Bc
0 0 0 1 1 0 2 bC
0 0 0 1 0 1 2 bc
0 0 0 0 1 1 2 Cc
1 0 0 0 0 0 1 A
0 1 0 0 0 0 1 a
0 0 1 0 0 0 1 B
0 0 0 1 0 0 1 b
0 0 0 0 1 0 1 C
0 0 0 0 0 1 1 c
0 0 0 0 0 0 0
Business Accounts
Answer for Membership
by: ozoPosted on 2009-05-01 at 22:23:33ID: 24284940
valid states are
AaBbCc
AaBbC c
AaBbC c
AaBb Cc
AaBb C c
AaBb c C
AaBb Cc
AaBCc b
AaBC bc
AaBC b c
AaB bc C
AaB b Cc
AaBCc b
AaBC c b
AaBC bc
AaB Cc b
AaB C bc
AaCc Bb
AaC Bb c
Aa BbCc
Aa BbC c
Aa Bb Cc
AaCc B b
AaC B bc
Aa BCc b
Aa BC bc
AaCc b B
AaC bc B
Aa bc BC
Aa b BCc
AaCc Bb
AaC c Bb
Aa Cc Bb
Aa c BbC
Aa BbCc
ABbCc a
ABbC ac
ABbC a c
ABb ac C
ABb a Cc
ABCc ab
ABC abc
ABC ab c
AB abc C
AB ab Cc
ABCc a b
ABC ac b
ABC a bc
ACc ab B
AC abc B
A abc BC
A ab BCc
ACc a Bb
AC ac Bb
A ac BbC
A a BbCc
ABbCc a
ABbC c a
ABbC ac
ABb Cc a
ABb C ac
ABCc b a
ABC bc a
ABC b ac
ABCc ab
ABC c ab
ABC abc
AB Cc ab
AB C abc
ACc Bb a
AC Bb ac
A BbCc a
A BbC ac
ACc B ab
AC B abc
A BCc ab
A BC abc
abc ABC
ab ABCc
ab ABC c
abc AB C
ab AB Cc
ac ABbC
a ABbCc
a ABbC c
ac ABb C
a ABb Cc
ac ABC b
a ABCc b
a ABC bc
abc AC B
ab ACc B
abc A BC
ab A BCc
ac AC Bb
a ACc Bb
ac A BbC
a A BbCc
BbCc Aa
BbC Aa c
Bb AaCc
Bb AaC c
Bb Aa Cc
BCc Aa b
BC Aa bc
B AaCc b
B AaC bc
bc AaBC
b AaBCc
b AaBC c
bc AaB C
b AaB Cc
Cc AaBb
C AaBb c
c AaBbC
AaBbCc
AaBbC c
c AaBb C
AaBb Cc
Cc AaB b
C AaB bc
c AaBC b
AaBCc b
AaBC bc
bc AaC B
b AaCc B
bc Aa BC
b Aa BCc
Cc Aa Bb
c AaC Bb
AaCc Bb
c Aa BbC
Aa BbCc
BbCc A a
BbC A ac
Bb ACc a
Bb AC ac
BCc A ab
BC A abc
B ACc ab
B AC abc
bc ABC a
b ABCc a
b ABC ac
Cc ABb a
C ABb ac
c ABbC a
ABbCc a
ABbC ac
Cc AB ab
C AB abc
c ABC ab
ABCc ab
ABC abc
abc BC A
ab BCc A
abc B AC
ab B ACc
ac BbC A
a BbCc A
ac Bb AC
a Bb ACc
abc C AB
ab Cc AB
abc ABC
ab c ABC
ab ABCc
ac b ABC
a bc ABC
a b ABCc
ac C ABb
a Cc ABb
ac ABbC
a c ABbC
a ABbCc
BbCc a A
BbC ac A
Bb ac AC
Bb a ACc
BCc ab A
BC abc A
B abc AC
B ab ACc
bc a ABC
b ac ABC
b a ABCc
Cc ab AB
C abc AB
c ab ABC
abc ABC
ab ABCc
Cc a ABb
C ac ABb
c a ABbC
ac ABbC
a ABbCc
BbCc Aa
BbC c Aa
Bb Cc Aa
Bb c AaC
Bb AaCc
BCc b Aa
BC bc Aa
B bc AaC
B b AaCc
bc BC Aa
b BCc Aa
bc B AaC
b B AaCc
Cc Bb Aa
c BbC Aa
BbCc Aa
c Bb AaC
Bb AaCc
bc C AaB
b Cc AaB
bc AaBC
b c AaBC
b AaBCc
Cc b AaB
C bc AaB
c b AaBC
bc AaBC
b AaBCc
Cc AaBb
C c AaBb
c C AaBb
Cc AaBb
c AaBbC
c AaBbC
AaBbCc