Question

How do i convert a hex to base64? any sample ANSI C code?

Asked by: realjr

I have a to decode a data to base64 string. I have the hex value of each character of a base64 string.

my limited knowledge is through this:
http://en.wikipedia.org/wiki/Base64

where you can convert a hex to decimal and then to base64 string base on the logic.

are there any simple and efficient ANSI C code available (without linking to other base64.h codes)

thanks!

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Asked On
2009-08-05 at 10:11:43ID24628830
Topic

Algorithms

Participating Experts
3
Points
500
Comments
11

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Answers

 

by: thehagmanPosted on 2009-08-05 at 13:33:26ID: 25027824

Each character in base64 encodes 6 bits, each character in hex encodes 4 bits.
Therefore it is more efficient to avoid any decimal intermediate.
Three hex digits produce 2 base64 cracters.
If these three hex digits correspond to numerical values x,y,z, then
the first base64 character corresponds to (x<<2) + (y>>2) and the second to ((y & 3)<< 4) + z.

 

by: realjrPosted on 2009-08-05 at 18:50:53ID: 25029494

great! thanks, do you have sample ANSI C code (even just the logic part)

 

by: realjrPosted on 2009-08-05 at 21:08:43ID: 25030063

any sample code for 500 points?
thanks!

 

by: Infinity08Posted on 2009-08-05 at 22:01:44ID: 25030235

The wiki you mentioned contains a link to this ANSI C implementation :

        http://base64.sourceforge.net/b64.c

Would that suit your needs ? If not, why not ?

 

by: t0t0Posted on 2009-08-06 at 13:36:48ID: 25037802

interesting question.....

 

by: Infinity08Posted on 2009-08-06 at 13:56:25ID: 25037976

I suddenly had to think back to this question :

        http://www.experts-exchange.com/Programming/Languages/CPP/Q_21988706.html

That was a fun challenge :)

 

by: t0t0Posted on 2009-08-06 at 16:12:18ID: 25038915

The following data strings will simplify your algorithm:

   BIN  = 0000000100100011010001010110011110001001101010111100110111101111
   HEX = 0123456789ABCDEF
   B64  = ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/

Use the BIN string to initialise an array of nybbles which will be indexed by their equivalent HEX value as in the following:

    h[0] = 0000
    h[1] = 0001
    :
    h[9] = 1001
    h[A] = 1010
    :
    h[F] = 1111

So the array h[ ] will be indexed by the enumerated types 0~9, A~F.

Therefore, if you were to input the value '5FA' in hex, then a loop could take each character in turn using something similar to the MID$() function and produce the following results:

   h[5] = 0101
   h[F] = 1111
   h[A] = 1010

During each iteration of the loop, you could append these nybbles to a string as in the following:

   binary$ = h[5] + h[F] + h[A]

This would produce the following:

   binary$ = 010111111010

The code for this might look something like the following:

   LET hex$ = 5FA

   FOR i = 0 TO LEN(hex$ - 1) STEP 1
      LET binary$ = binary$ + h[MID$(hex$, i, 1))]
   NEXT i


The next process involves two stages: converting 6-bit parts to decimal and then using this decimal value to index the B64 string above to return the equivalent base-64 character.

Again, using something similar to the MID$ function, loop through the binary$ string in steps of 6 thereby selecting 6 binary bits at a time and convert them their decimal value. The following will step through the binary$ string:

   FOR i = 0 TO LEN(binary$ - 1) STEP 6
      LET 6bits = MID$(binary$, i, 6)
      :
   NEXT i


Before doing this, it may be necessary to pad the binary$ string with leading zeros so that it's length is a multiple of 6. Doing so, you would then need to check whether the first 6 bits are all zero and if so, chop them off.


Inside the FOR loop, you would need to convert the 6-bit binary value to decimal as in the following:

   LET decimal = 0
   LET multiplyer = 1

   FOR i = 5 TO 0 STEP -1
      IF MID$(6bit$, i, 1) = 1 THEN LET decimal = decimal + multiplyer
      LET muliplyer = multiplyer x 2
   NEXT i

At this stage, you will have a decimal value which can now be used to index the B64 string above, as in:

   LET base64$ = B64[decimal]

For each iteration of the first FOR loop, the value returned by B64[decimal] is appended to the base64$ string using the following:

   LET base64$ = base64$ = B64[decimal]


And there you have it.

I have used a pseudo-code approach in my explanation which I hope makes sense to you.

 

by: Infinity08Posted on 2009-08-06 at 22:59:28ID: 25040206

>> Before doing this, it may be necessary to pad the binary$ string with leading zeros so that it's length is a multiple of 6.

A Base64 encoding uses '=' characters at the end for padding it to a multiple of 3 characters. You don't have to add any further padding ... Just process the data 6 bits at a time (or multiples of 6 bits, depending on your approach).

An "easy" approach is to process the Base64 data 4 characters (24 bits) at a time, which corresponds to 3 bytes of binary data. And vice versa.

There are lookup table approaches of all kinds, platform specific optimizations, etc.

Base64 can be explained quite simply like this :

encoding : Take binary data, and split it up in blocks of 6 bits. Each such block is mapped to a character in the Base64 alphabet (A-Z, a-z, 0-9, '+' and '/'), which is pushed on the output stream.

decoding : Take each character, and transform it to the original block of 6 bits it corresponds to by using the Base64 alphabet, and push those 6 bits on the output stream.

That's it.

 

by: t0t0Posted on 2009-08-07 at 02:50:17ID: 25041168

Infinty08
I thought this was an academic exercise in developing an algorithm so I re-read the question and realise the asker wants C code and, quite possibly, develop a program to convert a stream (file-to-file, say) from hex to base64.

Under those circumstances, I agree it is easier to decode 3 octets at a time and that padding with '=' is the usual approach.

For speed, I would define two arrays: h[...], as described in my previous post:

   h[0] = 0000
   h[1] = 0001
   :
   h[9] = 1001
   h[A] = 1010
   :
   h[F] = 1111

indexed by enumerated types 0~9, A~F and, another b64[...]:

   b64[000000] = A
   b64[000001] = B
   b64[000010] = C
   :
   b64[111101] = 9
   b64[111110] = +
   b64[111111] = /

indexed by enurated sextets.

Then, simply read in 3 hex digits at a time. Convert them to their corresponding nibbles like this:

(As an example, our stream starts like this: 2FA50F6... therefore,

   digits read in = '2', 'F' and 'A'

these are read into a variable ch, so,

   ch = '2' therefore, h[ch] = '0010'         --> append this to our binary string. Binary = 0010

   ch = 'F' therefore, h[ch] = '1111'         --> append this to our binary string. Binary = 00101111

   ch = 'A' therefore, h[ch] = '1010'         --> append this to our binary string. Binary = 001011111010

we now arrive at a 2-sextet wide binary string which we can split into 2 separate sextet enumerate patterns which are used to index the b64[...] array as in the following:

   sextet = '001011' therefore, b64[sextet] = 'K'        --> append to base64 string. Base64 = K

   sextet = '111010' therefore, b64[sextet] = '6'         --> append to base64 string. Base64 = K6

and continue this process for all the hex digits padding with '=' at the end if necessary.

So, rather than actually perform any arithmetical calculations, simply use the values obtained as indicies to obtain the translated value from hex, to sextets, to base64.

 

by: Infinity08Posted on 2009-08-07 at 03:21:09ID: 25041299

>> and that padding with '=' is the usual approach.

It's THE approach defined by Base64 ;)

If you want speed, consider reading through the link I posted earlier ... heh :)

 

by: t0t0Posted on 2009-08-07 at 09:39:48ID: 25044593

Infinty08

Interesting thread - pity I missed that one at the time.

20120131-EE-VQP-002

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