Question

Math Matrix, calculate permutations, VBA

Asked by: jondanger

Hi Experts,

I need a loop that generates the following output...

1st:[0,0,1],[0,0,1],[0,0,1],[0,0,1],[0,0,1],[0,0,1]
2nd:[0,0,1],[0,0,1],[0,0,1],[0,0,1],[0,0,1],[0,1,0]
3rd:[0,0,1],[0,0,1],[0,0,1],[0,0,1],[0,0,1],[1,0,0]
4th:[0,0,1],[0,0,1],[0,0,1],[0,0,1],[0,1,0],[0,0,1]
5th......


There can only be one 1 inside each [], it has to be in position a, b or c.

Therefore i think 3^6 = 729 possible combinations.

And it makes sense that:
729th: [1,0,0],[1,0,0],[1,0,0],[1,0,0],[1,0,0],[1,0,0]

Answers in VBA please!

Many thanks!

Jon

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Asked On
2009-11-04 at 13:31:17ID24872592
Tags

Matrix

,

Loops

,

VBA

Topics

Algorithms

,

Math & Science

,

Microsoft Excel Spreadsheet Software

Participating Experts
2
Points
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Comments
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Answers

 

by: matthewspatrickPosted on 2009-11-04 at 15:08:42ID: 25745102

Hello jondanger,

This seems to be doing it...



Sub DoIt()
   
    Dim x1 As Long, x2 As Long, x3 As Long, x4 As Long, x5 As Long, x6 As Long
    Dim r As Long
    Dim BigArr(1 To 6) As String
    Dim SmArr(1 To 3) As String
   
    Workbooks.Add
   
    For x1 = 1 To 3
        For x2 = 1 To 3
            For x3 = 1 To 3
                For x4 = 1 To 3
                    For x5 = 1 To 3
                        For x6 = 1 To 3
                            SmArr(1) = IIf(x1 = 1, 1, 0)
                            SmArr(2) = IIf(x1 = 2, 1, 0)
                            SmArr(3) = IIf(x1 = 3, 1, 0)
                            BigArr(1) = "[" & Join(SmArr, ",") & "]"
                            SmArr(1) = IIf(x2 = 1, 1, 0)
                            SmArr(2) = IIf(x2 = 2, 1, 0)
                            SmArr(3) = IIf(x2 = 3, 1, 0)
                            BigArr(2) = "[" & Join(SmArr, ",") & "]"
                            SmArr(1) = IIf(x3 = 1, 1, 0)
                            SmArr(2) = IIf(x3 = 2, 1, 0)
                            SmArr(3) = IIf(x3 = 3, 1, 0)
                            BigArr(3) = "[" & Join(SmArr, ",") & "]"
                            SmArr(1) = IIf(x4 = 1, 1, 0)
                            SmArr(2) = IIf(x4 = 2, 1, 0)
                            SmArr(3) = IIf(x4 = 3, 1, 0)
                            BigArr(4) = "[" & Join(SmArr, ",") & "]"
                            SmArr(1) = IIf(x5 = 1, 1, 0)
                            SmArr(2) = IIf(x5 = 2, 1, 0)
                            SmArr(3) = IIf(x5 = 3, 1, 0)
                            BigArr(5) = "[" & Join(SmArr, ",") & "]"
                            SmArr(1) = IIf(x6 = 1, 1, 0)
                            SmArr(2) = IIf(x6 = 2, 1, 0)
                            SmArr(3) = IIf(x6 = 3, 1, 0)
                            BigArr(6) = "[" & Join(SmArr, ",") & "]"
                            r = r + 1
                            Cells(r, 1) = Join(BigArr, ",")
                        Next
                    Next
                Next
            Next
        Next
    Next
   
    MsgBox "Done"
   
End Sub


Regards,

Patrick

 

by: harfangPosted on 2009-11-04 at 15:20:42ID: 25745215

You are basically counting in base three, using "digits" like "[0,0,1]". Counting is easy.

(°v°)

Sub TheLoop()
    
    Dim strOut As String
    Dim i As Integer
    Dim n As Integer
    Dim m As Integer
    
    For n = 0 To 3 ^ 6 - 1
        m = n
        strOut = ""
        For i = 1 To 6
            strOut = Choose(m Mod 3 + 1, ",[0,0,1]", ",[0,1,0]", ",[1,0,0]") & strOut
            m = m \ 3
        Next i
        Mid(strOut, 1, 1) = ":"
        Debug.Print n, strOut
    Next n
    
End Sub

                                              
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by: jondangerPosted on 2009-11-07 at 06:10:39ID: 31650245

excellent. both work flawlessly.

20120131-EE-VQP-002

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