I had tried that already, practically the same result as I had with Pos() and Replace() functions.
Thanks for your help anyway
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How can I remove newline character from a string
Hello,
I might have a string which contains text, newline characters and spaces which is fine.
And also, I might have a string which contains just newline characters or just spaces or both, which is not fine.
I can remove spaces by using function TRIM(), but I am not sure how to remove newline characters from the string.
I am thinking of using functions Pos() and Replace() in a loop to replace newline characters with nothing, but it is does not look like an altimate way to solve this problem.
Is there any other simpler way to remove newline characters from a string or my choices are limited and I have to use Pos(0 and Replace() functions.
Thank you
elyubron
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Answers
I guess the Replace way is way to go...
May be you can use PFC string service function of_glabalreplace() instead, will mean less code.
If not using PFC , you can download stand-alone pfc services from http://pfcguide.com/downlo
Some of these services are really handy(specially string service) and will help a lot in your other coding also.
If you are getting this String from database, you can use the Database TRIM function and specify which character to Trim.
Match might work in some cases ( to find such occurance, to remove these characters you will still need to user replace..) ...
Regards,
Vikas Dixit
Hi,
Don't use '~n' for comparison.Instead use ascii value of it.
Use ASC function to find the newline character.
Try this
string ls_text,ls_temp
integer li_count
ls_text = 'Hello~nWorld'
for li_count = 1 To Len(ls_text)
ls_char = Mid(ls_text,li_count,1)
If Asc(ls_char) <> 10 Then
ls_temp = ls_temp + ls_char
End If
Next
Messagebox('',ls_temp)
If your text includes carriage return also then modify the if condition as below
If Asc(ls_char) <> 10 AND Asc(ls_char) <> 13 Then
ls_temp = ls_temp + ls_char
End If
Regards,
-Sandeep
Hi,
i have checked that following solution is also working you can use that also.....
long start_pos=1
string old_str, new_str, mystring
mystring = mle_1.Text //// OR mystring = 'Hello~nWorld'
old_str = "~n"
new_str = ""
// Find the first occurrence of old_str.
start_pos = Pos(mystring, old_str, start_pos)
// Only enter the loop if you find old_str.
DO WHILE start_pos > 0
// Replace old_str with new_str.
mystring = Replace(mystring, start_pos, Len(old_str), new_str)
// Find the next occurrence of old_str.
start_pos = Pos(mystring, old_str, start_pos+Len(new_str))
LOOP
mle_1.Text = mystring
Let me know if you have any problem.
Regards,
Sandeep
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by: DeanHorakPosted on 2005-11-10 at 11:41:43ID: 15268514
You can use character arrays - might be more efficient....
i.e.
function String stripcr(String str) - where return value is string and argument is string
///////// function body...
char carray[]
String retStr
carray = str
int i,j,l
l = len(str)
FOR i=1 to l
if carray[i] = "~n" THEN // remove newline
FOR j=i to l - 1
carray[j] = carray[j+1]
NEXT
carray[l] = CHAR(0)
END IF
NEXT
retStr = carray
return retStr