Question

powerbuilder string validation, editmask

Asked by: basilhs_s

i want to create a function that it will accepts two argunents a string and a mask (pattern)
pattern should be something like xx.xx.xxx.xxxx

we want the function to return a value 0 if the input string follows  the pattern else 1
for example
if pattern is xx.xx.xxx.xxx
correct values are
60
60.00
60.00.000
60.00.000.000

non acceptable values are
60.0
60.  .00
   .00.0
xx.yy.zzz (only 0-9 are allowed ,neither letters nor spaces )

input string comes from a datawindow. its editmast.mask property has the same pattern. can we give an appropriate value to editmask.mask to do the same validation?

any ideas?

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Asked On
2009-05-27 at 04:27:04ID24441026
Tags

powerbuilder

,

editmask

Topic

PowerBuilder Programming Language

Participating Experts
1
Points
500
Comments
3

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Answers

 

by: sandeep_patelPosted on 2009-05-27 at 20:17:37ID: 24489505

Try this... not sure if any generalised approach is possible

string ls_str
boolean lb_result

ls_str = sle_1.Text

Choose Case 1=1
      Case match(ls_str,"^[0-9][0-9]$")
            Messagebox('1','true')
            Return
      Case match(ls_str,"^[0-9][0-9]\.[0-9][0-9]$")
            Messagebox('2','true')
            Return
      Case match(ls_str,"^[0-9][0-9]\.[0-9][0-9]\.[0-9][0-9][0-9]$")
            Messagebox('3','true')
            Return
      Case match(ls_str,"^[0-9][0-9]\.[0-9][0-9]\.[0-9][0-9][0-9]\.[0-9][0-9][0-9]$")
            Messagebox('4','true')
            Return
End Choose

Messagebox('5','false')

Regards,
Sandeep

 

by: sandeep_patelPosted on 2009-05-27 at 20:50:09ID: 24489597

This is bit more generalised

string ls_pattern,ls_temp
integer li_count

ls_str = sle_1.Text
ls_pattern = 'XX.XX.XXX.XXX'
ls_temp = ls_str
For li_count = 1 To len(ls_str)
      If IsNumber(Mid(ls_temp,li_count,1)) Then
            ls_temp = Replace(ls_temp,li_count,1,'X')
      End If
Next

If len(ls_temp) < len(ls_pattern) Then
      ls_temp = ls_temp + '.'
End If

If Pos(ls_pattern,ls_temp,1) > 0 AND isnumber(ls_str) Then
      messagebox('','match')
else
      messagebox('','no match')
end if

 

by: basilhs_sPosted on 2009-05-28 at 05:44:50ID: 31585707

perfect approach. it helped me a lot

20120131-EE-VQP-002

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