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8.8

multiple new on the same Reference

Asked by epsilon777 in Game Programming, C++ Programming Language

Tags: multiple new reference

Hie all,

In my code i've done this (I know you don't have the full code, but may be someone would understand something without all the code)

ICard& c2c = * new Card52 ( ClassicalCard::KING, ClassicalCard::DIAMOND );
cout << "c2c:" << c2c << endl;

c2c = * new Card52 ( ClassicalCard::QUEEN, ClassicalCard::DIAMOND );
cout << "c2c:" << c2c << endl;

//default values are nor KING nor QUEEN
the ouput of this is:

c2c:[KD]
c2c:[KD]

as the second new couldn't affect the variable!! (that's my problem)

But if i do this
#include <iostream>

using namespace std;

class A {
public:
explicit A ( int i ) : m_i ( i ) {
}
virtual ~A ( ) {
}
void foo ( void ) {
cout << "A::foo::m_i :\t" << m_i << endl;
}
int m_i;
};

int main()
{
A a = * new A ( 0 );
a.foo ( );
a = * new A ( 1 );
a.foo ( );
return 0;
}

I get the folowing output:
A::foo::m_i : 0
A::foo::m_i : 1

This time the second new is ok!!!!

BUT from: http://en.wikipedia.org/wiki/Reference_(C%2B%2B)
[...]
Once a reference is created, it cannot be later made to reference another object; it cannot be reseated. This is often done with pointers.
[...]

so if i do a "FOO& f = * new someything" am i able to do again "f = * new something" or not???

I can't understand why my program [card52] does not function properly (it seems, the c2c reference point always the same object even after the second new)
But if i try the example above with class A i don't have the same comprtment, as i was able to do any number of new on the same variable
Could someone explain me those thing?

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multiple new on the same Reference

Asked by epsilon777 in Game Programming, C++ Programming Language

Tags: multiple new reference

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