\d{0,6}(\.\d{1,2})?
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Question
Decimal RegEx C#
Hi
I am using (\d{1,6})(\.[0-9]{1,2})? to enter a decimal value. But, when the number is just a fraction, the user will enter dot then 2 digits. Unfortunately, this is now working. He has to enter a zero before dot to be accepted.
How can I change it to add zero directly after he pressed dot to be 0.
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Answers
if you just want to allow users to enter .## format, your regular expression should be like this:
\d{0,6}(\.\d{1,2})?
But if you want to replace "." wih "0." if dot is the first key then you can handle the keypress event like this:
private void textBox1_KeyPress(object sender, KeyPressEventArgs e)
{
if (e.KeyChar == 46 && textBox1.Text.Length == 0)
{
e.Handled = true;
textBox1.Text = "0.";
textBox1.SelectionStart = textBox1.Text.Length+1;
}
}
and you can stll check the entered data, lets say on button click event like this:
private void btnTest_Click(object sender, EventArgs e)
{
if (Regex.IsMatch(textBox1.Te
{
label1.Text = Convert.ToDecimal(textBox1
}
}
Hope it helps
Regex alone can not replace "." with "0." while he data is getting entered unless you handle the keydown, keypress etc. events. if your goal is to replace the "." if it is the first character entered into to the txtbox then yes you should handle the keypress event but if you are ok to apply the regex to the entered data:
\d{0,6}(\.\d{1,2})?
above regex will do the job and once it's converted to decimal or double "0" will be automatically added to the entered value.
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by: kaufmedPosted on 2009-11-04 at 16:14:35ID: 25745599
You could change your regex to be:
(\d{,6})(\.[0-9]{1,2})?