Question

how to use regular expression to take out spaces, quotes, etc

Asked by: trevoray

can someone please show me in VB.NET how to use regular expression to take out quotes, spaces, etc from a string?

i am building a CSV list of email addresses, and i need to remove any quotes, spaces, etc.

thanks!

trevor

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Asked On
2003-09-22 at 07:24:13ID20745133
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Answers

 

by: morphinexPosted on 2003-09-22 at 07:37:12ID: 9406019

From MSDN Library, returns a string after stripping out all nonalphanumeric characters except @, - (a dash), and . (a period).


    Imports System.Text.RegularExpressions

    Public Function String_Cleaner(ByVal thisString As String) As String
        Try
            Return Regex.Replace(thisString, "[^\w\.@-]", "")
        Catch ex As Exception
            ErrorTrap(ex, System.Reflection.MethodInfo.GetCurrentMethod.Name, "" _
                        )
        End Try
    End Function

 

by: morphinexPosted on 2003-09-22 at 07:39:39ID: 9406032

Public Sub ErrorTrap(ByVal thisException As Exception, ByVal strMethodName As String, ByVal strMiscInfo As String) As Boolean
    MsgBox (ex.Message & " in this method: " & strMethodName & " Other Info: "  & strMiscInfo)
End Sub

 

by: trevorayPosted on 2003-09-22 at 07:51:43ID: 9406110

I am getting an error saying 'Name Regex is not declared'

 

by: morphinexPosted on 2003-09-22 at 08:04:46ID: 9406201

We can fix that... forget what I've written before, and use this.

    Public Function String_Cleaner(ByVal thisString As String) As String
        Try
            Return System.Text.RegularExpressions.Regex.Replace(thisString, "[^\w\.@-]", "")
        Catch ex As Exception
            MsgBox("Error Found")
        End Try
    End Function

 

by: trevorayPosted on 2003-09-22 at 08:05:57ID: 9406215

ok, i tried to compress all the above to:

Dim csvData As String = txtCC.Text
         
csvData = Replace(csvData, "[^\w\.@-]", "")

 

by: trevorayPosted on 2003-09-22 at 08:07:25ID: 9406225

part of my text was cut off.  my above post did now work. can you tell me how to make it work in the above format?

thanks!

 

by: trevorayPosted on 2003-09-22 at 08:08:05ID: 9406229

ugh!! i meant to say "did NOT work", not "did now work"

 

by: morphinexPosted on 2003-09-22 at 08:08:55ID: 9406237

That wouldn't work very well.  After putting in the code from my last message, you can put in..

Dim csvData as String = String_Cleaner(txtCC.Text)

 

by: trevorayPosted on 2003-09-22 at 08:28:20ID: 9406402

ok, the above worked, but it stripped out the commas of my csv string, thus making it inoperable.

i tried to add the comma to the function, like this:

Return System.Text.RegularExpressions.Regex.Replace(thisString, "[^\w\.@-,]", "")
        Catch ex As Exception

 

by: trevorayPosted on 2003-09-22 at 08:28:54ID: 9406410

but that only returns the following error:

The following exception occurred:

                       
System.InvalidOperationException: It is invalid to show a modal dialog or form when the application is not running in UserInteractive mode. Specify the ServiceNotification or DefaultDesktopOnly style to display a notification from a service application.
   at System.Windows.Forms.MessageBox.ShowCore(IWin32Window owner, String text, String caption, MessageBoxButtons buttons, MessageBoxIcon icon, MessageBoxDefaultButton defaultButton, MessageBoxOptions options)
   at System.Windows.Forms.MessageBox.Show(IWin32Window owner, String text, String caption, MessageBoxButtons buttons, MessageBoxIcon icon, MessageBoxDefaultButton defaultButton, MessageBoxOptions options)
   at Microsoft.VisualBasic.Interaction.MsgBox(Object Prompt, MsgBoxStyle Buttons, Object Title)
   at mbr_app._default.String_Cleaner(String thisString)
   at mbr_app._default.GetDataTable()
   at mbr_app._default.Send()

 

by: morphinexPosted on 2003-09-22 at 08:39:33ID: 9406509

Try sticking the , at the front... like..

Return System.Text.RegularExpressions.Regex.Replace(thisString, "[^\w\,.@-]", "")

 

by: trevorayPosted on 2003-09-22 at 08:48:40ID: 9406581

cool, that did it! would you mind explaining to me why it works when i stick it at the front, but doesn't work when it's stuck at the end?

 

by: fatethemePosted on 2003-09-22 at 09:47:03ID: 9407012

It's not the position of the comma, it's the position of the hyphen character.  The hyphen has to be either the first or the last character in a regex, otherwise the Regex class tries to define a range.  The comma could go last if you put the hyphen first, e.g.. @"[^-\w.@,]"

20120131-EE-VQP-002

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