Question

VB.net - How do I use a variable when referencing a text box name

Asked by: ssconce

Thanks in advance experts - I am a newbie - I have a loop that performs a sql query that counts all records in a table - I want to add that value to a different text box each time ti loops - my first text box name is txt0 - then txt1, txt2 and so on - as it loops I thought I could use somthing like this for the reference - -  - txt & (i).text = what ever - does not work .... im guesing a syntax problem - i would think ther must be a way to do this any help would be great - thanks

Public Class Form1
    Private Sub btnTest_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnTest.Click
        Dim con As New OleDb.OleDbConnection
        Dim dbProvider As String
        Dim da As New OleDb.OleDbDataAdapter
        Dim ds As New DataSet
        Dim sql As String
        Dim cb As New OleDb.OleDbCommandBuilder(da)
        Dim fileReader As New System.IO.StreamReader("C:\ServerList\ServerList.txt")
        Dim Server As String
        Dim fileContents() As String = fileReader.ReadToEnd.Split(ControlChars.Cr)
        Dim lines As String() = IO.File.ReadAllLines("C:\ServerList\ServerList.txt")
        Dim startnum As Integer
        Dim endnum As Integer
 
        startnum = 0
        endnum = lines.Length - 1
 
        For i = startnum To endnum
            MsgBox(i)
            Server = fileContents(i).Replace(vbLf, String.Empty).Replace(vbCr, String.Empty)
            dbProvider = "provider = sqloledb;Data Source=" & Server & ";Initial Catalog=Windman;User ID=username;Password=password"
            sql = "SELECT COUNT(*) AS Expr1 FROM TClientNotificationBuffer"
            con = New OleDb.OleDbConnection(dbProvider)
            con.Open()
            da = New OleDb.OleDbDataAdapter(sql, con)
            da.Fill(ds, "AlarmCount")
            "txt" & i.Text = ds.Tables("AlarmCount").Rows(0).Item(0)
            con.Close()
        Next i
    End Sub
End Class

                                  
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Asked On
2009-10-15 at 15:35:43ID24816622
Topics

.NET

,

Visual Studio

Participating Experts
1
Points
500
Comments
3

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Answers

 

by: Idle_MindPosted on 2009-10-15 at 16:11:41ID: 25585771

You could do:

        For i = startnum To endnum
            Server = fileContents(i).Replace(vbLf, String.Empty).Replace(vbCr, String.Empty)
            dbProvider = "provider = sqloledb;Data Source=" & Server & ";Initial Catalog=Windman;User ID=username;Password=password"
            Sql = "SELECT COUNT(*) AS Expr1 FROM TClientNotificationBuffer"
            con = New OleDb.OleDbConnection(dbProvider)
            con.Open()
            da = New OleDb.OleDbDataAdapter(Sql, con)
            da.Fill(ds, "AlarmCount")
            Dim ctlName As String = "txt" & i
            Dim ctls() As Control = Me.Controls.Find(ctlName)
            If ctls.Length > 0 Then
                If TypeOf ctls(0) Is TextBox Then
                    Dim tb As TextBox = CType(ctls(0), TextBox)
                    tb.Text = ds.Tables("AlarmCount").Rows(0).Item(0)
                End If
            Else
                MessageBox.Show("Name: " & ctlName, "Control Not Found")
            End If
            con.Close()
        Next i
                                              
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by: Idle_MindPosted on 2009-10-15 at 16:13:03ID: 25585778

If your textboxes are NOT contained directly by the form (like in a Panel for instance) then change:

    Dim ctls() As Control = Me.Controls.Find(ctlName)

To:

    Dim ctls() As Control = Me.Controls.Find(ctlName, True)

 

by: ssconcePosted on 2009-10-15 at 18:29:11ID: 25586367

Thanks - I will not be able to try until the morning

20120131-EE-VQP-002

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