Question

Login to site using Httpwebrequest

Asked by: whythetorment

Hi,  

I have the following code that I'm using to login to a site.  It works fine on my other sites, but for some reason it just won't login into one specific site.  I've made like 10 times sure the username and password is correct.  Just don't know why it will not log in.  The website is :
www.fantasy-fashions.co.uk
The login page is : http://fantasy-fashions.co.uk/shop/index.php?main_page=login

I've gathered from the source of the page the textbox names are : login-email-address and login-password.  Just can't figure why its not logging in.

myHttpWebRequest = WebRequest.Create("http://fantasy-fashions.co.uk/shop/index.php?main_page=login")
                myHttpWebRequest.KeepAlive = False
          
                strPostData = "login-email-address=" & sEmailAddress & "&login-password=" & sPassword
 
                myHttpWebRequest.Method = "POST"
                myHttpWebRequest.CookieContainer = oCookies
 
                myHttpWebRequest.UserAgent = "User-Agent: Mozilla/5.0 (Windows; U; Windows NT 5.1; en-GB; rv:1.7.7) Gecko/20050414 Firefox/1.0.3"
                myHttpWebRequest.ContentType = "application/x-www-form-urlencoded"
 
                myHttpWebRequest.ContentLength = strPostData.Length
 
                sStreamWriter = New StreamWriter(myHttpWebRequest.GetRequestStream(), System.Text.Encoding.ASCII)
                sStreamWriter.Write(strPostData)
                sStreamWriter.Close()
 
                response = CType(myHttpWebRequest.GetResponse(), HttpWebResponse)
                Application.DoEvents()
 
                oCookies.Add(myHttpWebRequest.RequestUri, response.Cookies)
 
                sSource = New StreamReader(response.GetResponseStream()).ReadToEnd()

                                  
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Asked On
2009-10-19 at 03:52:00ID24823092
Tags

VB 2005

,

HttpWebRequest

Topics

.NET

,

.NET Framework 2.x

,

Microsoft Visual Basic.Net

Participating Experts
2
Points
100
Comments
14

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Answers

 

by: whythetormentPosted on 2009-10-19 at 04:08:30ID: 25604101

sEmailAddress and sPassword is just a string with my login credentials to the site.
Also, the declarations are as follows :

Dim strPostData As String
Dim myHttpWebRequest As HttpWebRequest
Dim sStreamWriter As StreamWriter
Dim response As HttpWebResponse
Dim sSource As String
Public ocookies As CookieContainer = New CookieContainer

                                              
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by: Surone1Posted on 2009-10-19 at 09:11:50ID: 25606508

seems like there's a bit more security on that site when you submit the logon form it goes to..

http://fantasy-fashions.co.uk/shop/index.php?main_page=login&action=process&zenid=814849editedb5cb6ba2f


so you would probably need to include the right zenid (and acton) in the page request.

 

by: whythetormentPosted on 2009-10-19 at 23:51:11ID: 25611542

Thank you.  I've tried the action=process a few times as well before I posted this.  

Also, when I first open the link http://fantasy-fashions.co.uk/shop/index.php?main_page=login&action=process or http://fantasy-fashions.co.uk/shop/index.php?main_page=login there is no zenid.  Meaning, I don't get the zenid when I go to these two pages.  I only seem to see it after I try logging it...

What I did was,
1.  I went to http://fantasy-fashions.co.uk/shop/index.php?main_page=login&action=process
2.  I got the zenid from the source
3.  I parsed it to with my email address and password
 zenid=ee43b7b89505603c4ee0bfc1049f1b01&login-email-address=sEmail&login-password=sPassword
4.  Then I ran my function as above again...

Still not logging it...

 

by: whythetormentPosted on 2009-10-19 at 23:54:04ID: 25611553

Increased points

 

by: DanRollinsPosted on 2009-10-23 at 20:41:52ID: 25650658

I think you need to use:

               strPostData = "login-email-address=" & sEmailAddress & "&password=" & sPassword

The ID is login-password, but the NAME is password

 

by: whythetormentPosted on 2009-10-24 at 02:05:55ID: 25651366

Hi,

Thanx, but I've already tried those as well... I've tried the following variations :
login-email-address=" sEmailAddress "&password=" &sPassword
login-email-address=" sEmailAddress "&login-password=" &sPassword
email-address=" sEmailAddress "&password=" &sPassword
email-address=" sEmailAddress "&login-password=" &sPassword

 

by: DanRollinsPosted on 2009-10-24 at 12:14:20ID: 25653799

All those things you tried will fail.  You need to use an & between parts of the string that are concatenated.

 

by: whythetormentPosted on 2009-10-25 at 10:31:58ID: 25657379

Yeah i know, i just forgot to add them in my post

 

by: DanRollinsPosted on 2009-10-25 at 17:18:12ID: 25659102

What I usually do is try the submit as a get" rather than a "post" and see what parameters are being passed.  For that page it is:

?email_address=aaa&password=bbb&securityToken=b09d34fc13122ae24ac8ed436cafca02&x=30&y=11

Perhaps adding the
    &x=30&y=11
will do the trick.

 

by: whythetormentPosted on 2009-10-27 at 00:38:33ID: 25669859

Thanx.  Will try that over the weekend and let you know.  Didn't even think of trying to do a GET.

 

by: whythetormentPosted on 2009-10-31 at 15:04:53ID: 25711744

Ok so my client decided not to use this site any more for her business.  So was trying all this for nothing.  Will award you the points anyway for trying to help :)

Thanx DanRollins...

 

by: whythetormentPosted on 2009-10-31 at 15:05:55ID: 31642830

As per my comment left before closing this.

20120131-EE-VQP-002

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