Question

VB.net - Date Format

Asked by: andyb7901

I have a date string which I want to format. Or even replace some charactors within it. It is currently 01.06.06.  I have tried:
Date = Format(Date, "dd/MM/yyyy") - but this doesnt seem to do any good? Is there anyway to replace the last 06, but not the first or second bits of the date?

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Asked On
2007-06-15 at 06:01:16ID22636189
Tags

date

,

format

Topics

Microsoft Visual Basic.Net

,

Visual Basic Programming

Participating Experts
3
Points
500
Comments
5

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Answers

 

by: kprestagePosted on 2007-06-15 at 06:07:14ID: 19291419

date = date.replace(".06",".2006")

or Date = Date.ToString("MM/dd/yyyy")

 

by: kprestagePosted on 2007-06-15 at 06:07:39ID: 19291424

nevermind...my first one wouldn't work, but the second should.

 

by: kprestagePosted on 2007-06-15 at 06:12:07ID: 19291455

       Dim d As String
        d = "01.06.06"
        d = Convert.ToDateTime(d).ToString("dd/MM/yyyy")
        MsgBox(d)

 

by: emoreauPosted on 2007-06-15 at 06:49:54ID: 19291805

I use this small method to convert dates from string to the date datatype:

    Public Enum enuDateFormat
        DDMMMYY
        MMDDYYYY
        MMsDDsYY
        MMsDDsYYYY
        YYMMDD
        YYYYMMDD
    End Enum

    Public Shared Function ToDate(ByVal pDateFormat As enuDateFormat, ByVal pDate As String) As Date
        If pDate Is Nothing Then
            Return Date.MinValue
        End If

        Try
            Dim intDay As Integer
            Dim intMonth As Integer
            Dim intYear As Integer

            pDate = pDate.Trim

            If pDate.Length = 0 Then
                Return Date.MinValue
            End If

            Select Case pDateFormat
                Case enuDateFormat.DDMMMYY
                    intDay = CInt(pDate.Substring(0, 2))
                    Select Case pDate.Substring(2, 3).Trim.ToUpper
                        Case "JAN" : intMonth = 1
                        Case "FEB" : intMonth = 2
                        Case "MAR" : intMonth = 3
                        Case "APR" : intMonth = 4
                        Case "MAY" : intMonth = 5
                        Case "JUN" : intMonth = 6
                        Case "JUL" : intMonth = 7
                        Case "AUG" : intMonth = 8
                        Case "SEP" : intMonth = 9
                        Case "OCT" : intMonth = 10
                        Case "NOV" : intMonth = 11
                        Case "DEC" : intMonth = 12
                    End Select
                    intYear = CInt(pDate.Substring(5, 2))

                Case enuDateFormat.MMDDYYYY
                    intMonth = CInt(pDate.Substring(0, 2))
                    intDay = CInt(pDate.Substring(2, 2))
                    intYear = CInt(pDate.Substring(4, 4))

                Case enuDateFormat.MMsDDsYY
                    intMonth = CInt(pDate.Substring(0, 2))
                    intDay = CInt(pDate.Substring(3, 2))
                    intYear = CInt(pDate.Substring(6, 2))

                Case enuDateFormat.MMsDDsYYYY
                    intMonth = CInt(pDate.Substring(0, 2))
                    intDay = CInt(pDate.Substring(3, 2))
                    intYear = CInt(pDate.Substring(6, 4))

                Case enuDateFormat.YYMMDD
                    intYear = CInt(pDate.Substring(0, 2))
                    intMonth = CInt(pDate.Substring(2, 2))
                    intDay = CInt(pDate.Substring(4, 2))

                Case enuDateFormat.YYYYMMDD
                    intYear = CInt(pDate.Substring(0, 4))
                    intMonth = CInt(pDate.Substring(4, 2))
                    intDay = CInt(pDate.Substring(6, 2))

                Case Else
                    intYear = Date.MinValue.Year
                    intMonth = Date.MinValue.Month
                    intDay = Date.MinValue.Day
            End Select

            If intYear <> Date.MinValue.Year AndAlso intYear < 100 Then
                If intYear >= 80 Then
                    intYear += 1900
                Else
                    intYear += 2000
                End If
            End If

            Return New Date(intYear, intMonth, intDay)

        Catch ex As Exception
            Return Date.MinValue
        End Try
    End Function

 

by: Erick37Posted on 2007-06-15 at 07:30:47ID: 19292172

If you're using VS2005 or later then ParseDateExact comes in handy:

'read the string in as a date
Dim dateString As String = "01.06.06"
Dim newDate As DateTime = Date.ParseExact(dateString, "MM.dd.yy", Nothing)

'format the date
Console.WriteLine(newDate.ToString("MM.dd.yyyy"))

'create a new date and control format
Console.WriteLine(New Date(2007, newDate.Month, newDate.Day).ToString("MM.dd.yyyy"))

20120131-EE-VQP-002

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