Question

Setting last field of data table to be a hyperlink

Asked by: -cr-

I have the code below and need to make the last field a hyperlink to VeiwQuoteID.aspx

  Dim EMailLogDataStoredProcedure As String

        Select Case Request.QueryString("sp")
            Case "1"
                EMailLogDataStoredProcedure = "usr_sel_EMailLog_BrokerAdministrationEMailLogOutput"
            Case "2"
                EMailLogDataStoredProcedure = "usr_sel_EMailLog_BrokerAdministrationEMailLogOutput_BrandedPageOwnerEMailOutput"
            Case "3"
                EMailLogDataStoredProcedure = "usr_sel_EMailLog_BrokerAdministrationEMailLogOutput_ManagerEmployeeEMailOutput"
        End Select
        Dim dt As New DataTable
        'dt.Columns.Add("ID", GetType(Integer))
        dt.Columns.Add("Sender", GetType(String))
        dt.Columns.Add("Recipient", GetType(String))
        dt.Columns.Add("Subject", GetType(String))
        dt.Columns.Add("SentDate", GetType(DateTime))
        dt.Columns.Add("View", GetType(String))

        'Dim Crypter As New Encryption64
        Dim strBrokerEmail As String = Request.Cookies("BrokerEMailAddress").Value
        'MsgBox(strBrokerEmail, MsgBoxStyle.Information, "Broker Email")
        Dim strSP As String = EMailLogDataStoredProcedure
        Dim EMailLogDataConnString As String = ConfigurationManager.AppSettings("***")
        Dim EMailLogDataConn As New SqlConnection(EMailLogDataConnString)
        Dim SQLEMailLogDataCmd As New SqlCommand(strSP, EMailLogDataConn)
        Dim EMailLogData As SqlDataReader
        SQLEMailLogDataCmd.CommandType = CommandType.StoredProcedure
        SQLEMailLogDataCmd.Parameters.AddWithValue("@BrokerEMailAddress", strBrokerEmail)
        SQLEMailLogDataCmd.Parameters.AddWithValue("@StartDate", StartDate.Text)
        SQLEMailLogDataCmd.Parameters.AddWithValue("@EndDate", EndDate.Text)
        EMailLogDataConn.Open()
        EMailLogData = SQLEMailLogDataCmd.ExecuteReader
        While EMailLogData.Read
            dt.Rows.Add(New Object() {LCase(EMailLogData("Sender")), LCase(EMailLogData("Recipient")), LCase(EMailLogData("Subject")), LCase(EMailLogData("SentDate")), LCase(EMailLogData("QuoteID"))})
        End While

        If EMailLogData.HasRows = False Then
            lblNoResults.Visible = False
            lblNoResults.Text = "**Sorry there were no results for your query"
            lblNoResults.Visible = True
        End If
        If EMailLogData.HasRows = True Then
            lblNoResults.Visible = False
            Grid1.DataSource = dt
            Grid1.DataBind()
            Grid1.Visible = True
        End If
        SQLEMailLogDataCmd.Dispose()
        SQLEMailLogDataCmd = Nothing
        EMailLogData.Close()
        EMailLogData = Nothing
        EMailLogDataConn.Close()
        EMailLogDataConn.Dispose()
        EMailLogDataConn = Nothing
        EMailLogDataConnString = Nothing

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Asked On
2007-10-27 at 15:37:41ID22922444
Tags

datatable

,

hyperlink

Topics

Microsoft Visual Basic.Net

,

Visual Studio

,

.Net Editors & IDEs

Participating Experts
2
Points
500
Comments
4

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Answers

 

by: adam_pedleyPosted on 2007-10-27 at 18:34:29ID: 20163393

I imagine the reason you want to set the last column a hyperlink because you want to have the hyperlink in the GridView

Which project type are you using ASP.NET or Windows Application

if its ASP.NET in the markup you can go
            <asp:TemplateField>
        <ItemTemplate>
    <%# "<a href='viewQuoteID.aspx?ID=" & Eval("fieldname") & "'>" & Eval("otherfieldname") & "</a>" %>

        </ItemTemplate>
    </asp:TemplateField>

just a note that the # could be an = sign (i currently cant remember which one it is)

<asp

 

by: adam_pedleyPosted on 2007-10-27 at 18:37:11ID: 20163400

Or the other way is to loop through each row in the datatable before you send it to the gridview

DIm newDt as new datatable

for each dbrow as string in dt.rows
    dbrow.Item("field") = "<a href='viewQuote.aspx'>Link</a>"
   
    newDt.rows.add(dbrow)

Next

ofcourse my first approach is the best if its ASP.NET with a gridview

 

by: vbturboPosted on 2007-10-28 at 02:09:43ID: 20164105

'Try this


'Prøv denne her klasse som håndterer hyperlinks

Class Form34
    Inherits Form
   
    Private dt As DataTable = New DataTable
   
    Public Sub New()
        MyBase.New
        InitializeComponent
    End Sub
   
    Private Sub Form34_Load(ByVal sender As Object, ByVal e As EventArgs)
        dt.Columns.Add("id")
        dt.Columns.Add("link")
        dt.Rows.Add("1", "http://www.microsoft.com")
        dt.Rows.Add("2", "http://www.google.com")
        dt.AcceptChanges
        Me.dataGridView1.DataSource = dt
        Me.dataGridView1.Columns.RemoveAt(1)
        Dim dgvlc As DataGridViewLinkColumn = New DataGridViewLinkColumn
        dgvlc.DataPropertyName = "link"
        'bind to the correct data column
        dgvlc.HeaderText = "Link"
        dgvlc.Width = 260
        Me.dataGridView1.Columns.Add(dgvlc)
        AddHandler dataGridView1.CellContentClick, AddressOf Me.dataGridView1_CellContentClick
    End Sub
   
    Private Sub dataGridView1_CellContentClick(ByVal sender As Object, ByVal e As DataGridViewCellEventArgs)
        If (TypeOf Me.dataGridView1.Columns(e.ColumnIndex) Is DataGridViewLinkColumn) Then
            'do your stuff here
            Dim link As String = Me.dataGridView1(e.ColumnIndex, e.RowIndex).Value.ToString
            System.Diagnostics.Process.Start(link)
        End If
    End Sub
End Class

vbturbo

 

by: -cr-Posted on 2007-10-28 at 07:55:52ID: 20165157

Adam,
I ended up doing the same as metioned in the accepted solution prior to seeing your solution. Awarded points for that reason. Thanks for your help.

20120131-EE-VQP-002

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