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8.1

Accessing multidimensional arrays without using the [ ] notation to access an array element

Asked by nocturn4l in Microsoft Visual C++.Net, Microsoft Visual C++, C++ Programming Language

Tags: C++

I'm having trouble accessing the multidimensional array using pointers........(we're not allowed to use the [ ] notation to access an array element)

in the 2nd to last loop for example i'm using

row[a][b]=b;

when i can't be using that

i know to access the first row of row i can just do

*(row + number) = ....

which is equivalent to

row[number]

but how can i access the 2nd column of the array?

(which would be equivalent to row[num][num])


been lookin at my book and inet and not finding anything..
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#include <iostream>
using namespace std; 
typedef int *intptr; 
int main()
{
	int num; 
	cout << "Enter a number: ";
	cin >> num; 
	if(num%2==0) //even number
	{
	}
	else //odd number
	{
		intptr *row = new intptr[num];
		intptr col = new int[num]; 
		for(int a=0;a<num;a++){
			*(row + a) = col;
		} 
		for(int a=0;a<num;a++){
			for(int b=0;b<num;b++){
				row[a][b]=b;
			}
		} 
		for(int a=0;a<num;a++){
		for(int b=0;b<num;b++){
			cout << row[a][b] << " ";
		}
		cout << endl;
		}
	} 
	cin.get();
	cin.get();
	return 0;
}
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Zones: Microsoft Visual C++.Net, Microsoft Visual C++, C++ Programming Language
Tags: C++
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Solution Provided By: trinitrotoluene
Participating Experts: 5
Solution Grade: A
 
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