how to get the file with certain name in a directory which contains many files

  FileStream^ fs = File::OpenRead( pathOfIleGoesHere );

i need to open the file(from a directory with many files)  which contains the name new in the file name? can you please give code example?
directory="c:\test\"
no of files in it are 100 and one of the file name is
"te****_new.csv" how do i pick that up
thanks for your help

Please try:

String^ directory="c:\test\";
array<String^>^files = Directory::GetFiles( directory, "te*_new.csv" ); // or "te????_new.csv", if exactly 4 chars

if (files->Length > 0)
{
	FileStream^ fs = File::OpenRead( files[0] );

	// read the file here
}

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Here is how you can get all the files in a particular directory.   You would just need some logic on what to do with the name of the file (i.e. something to compare it to)

On Error Resume Next

Set objFSO = CreateObject("Scripting.FileSystemObject")
objStartFolder = "C:\test"

Set objFolder = objFSO.GetFolder(objStartFolder)

Set colFiles = objFolder.Files
For Each objFile in colFiles
	Wscript.Echo objFile.Name
Next

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