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| 07.20.2008 at 10:01PM PDT, ID: 23580938 |
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Attachment Details
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The Solution Rating System
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With so many solutions, how can you tell which solutions are most likely to help you and which ones are not? To provide you with a tool to use, we rate our solutions based on various elements that most accurately determine if a solution is a quality solution. To explain what factors affect the solution rating, here are the elements we take into consideration when formulating our solution rating.
Your Input Matters If you have any suggestions that you would like to make for our rating system, please ask a question in the Suggestions Zone of Community Support. Thank you! |
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Module Module1
Sub Main()
Dim EmployeeList As New List(Of Employee)
Dim Employee1 As New Employee
Dim Employee2 As New Employee
Employee1.ID = 1
Employee1.Name = "James"
Employee2.ID = 2
Employee2.Name = "james"
EmployeeList.Add(Employee1)
Console.WriteLine(EmployeeList.Contains(Employee2, New Employee.EqualityEmployee))
Console.ReadKey()
End Sub
Public Class Employee
Public ID As Int16
Public Name As String
Public Class EqualityEmployee
Implements IEqualityComparer(Of Employee)
Public Function Equals1(ByVal x As Employee, ByVal y As Employee) As Boolean Implements System.Collections.Generic.IEqualityComparer(Of Employee).Equals
Return x.ID.Equals(y.ID) OrElse String.Equals(x.Name, y.Name, StringComparison.CurrentCultureIgnoreCase)
End Function
Public Function GetHashCode1(ByVal obj As Employee) As Integer Implements System.Collections.Generic.IEqualityComparer(Of Employee).GetHashCode
Return obj.GetHashCode
End Function
End Class
End Class
End Module
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