Question

ASP.NET 2.0 / 3.5 GridView paging help needed !

Asked by: milani_lucie

Hi,

I have a GridView. And i set its properties like:

AllowPaging="true"
PageSize="4"

Now in the footer i have the paging like this, if i have more than 4 records:

1 2 3 4 5 6 7 8 9

I want to have ALL option with 1 2 3 4 5 6 7 8 9 means:

1 2 3 4 5 6 7 8 9 ALL

When user clicks on ALL it should display ALL the records.

Can you please provide me the code to achieve this ?

Thanks

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Asked On
2008-07-28 at 12:01:57ID23601831
Tags

Microsoft

,

ASP.NET

,

2.0 / 3.5

Topics

Visual Studio

,

Programming for ASP.NET

Participating Experts
1
Points
500
Comments
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Answers

 

by: b1xml2Posted on 2008-08-03 at 07:40:15ID: 22147669

  • It is at the RowCreated Event of the GridView, that you inject the additional link. So obviously at the GridView forexample: 

       <asp:GridView ID="UsersGridView" runat="server" AutoGenerateColumns="False"
            DataSourceID="UsersObjectDataSource" PageSize="2" AllowPaging="True"
            BackColor="White" BorderColor="#E7E7FF" BorderStyle="None" BorderWidth="1px"
            CellPadding="3" GridLines="Horizontal" onrowcreated="GridView_RowCreated">
           <FooterStyle BackColor="#B5C7DE" ForeColor="#4A3C8C" />
           <RowStyle BackColor="#E7E7FF" ForeColor="#4A3C8C" />
           <Columns>
               <asp:BoundField DataField="FirstName" HeaderText="First Name"  />
               <asp:BoundField DataField="LastName" HeaderText="Last Name" />
               <asp:BoundField DataField="Title" HeaderText="Title" />
           </Columns>
           <PagerStyle BackColor="#E7E7FF" ForeColor="#4A3C8C" HorizontalAlign="Right" />
           <SelectedRowStyle BackColor="#738A9C" Font-Bold="True" ForeColor="#F7F7F7" />
           <HeaderStyle BackColor="#4A3C8C" Font-Bold="True" ForeColor="#F7F7F7" />
           <AlternatingRowStyle BackColor="#F7F7F7" />
       </asp:GridView>
  • The PagerTable is the first control of the first cell of the PagerRow.
     
  • This object is marked as internal and is a subclass of the Table class.
     
  • Hence, we cast the control to the Table object and access the links on the first Row of the table. 
Please note that in event that the button "ALL" is clicked, the paging will be shut off and as such, you should expect to see the entire data without any pager.

        protected void SelectAll_Click(object sender, EventArgs e)
        {
            this.UsersGridView.AllowPaging = false;
            this.UsersGridView.DataBind();
        }
 
        protected void GridView_RowCreated(object sender, GridViewRowEventArgs e)
        {
            if (e.Row.RowType == DataControlRowType.Pager)
            {
                int count = e.Row.Cells.Count;
                if (e.Row.Cells.Count == 1 && e.Row.Cells[0].Controls.Count == 1)
                {
                    Table table = e.Row.Cells[0].Controls[0] as Table;
                    if (table != null && table.Rows.Count == 1)
                    {
                        TableCell cell = new TableCell { ID = "SelectAllCell" };
                        LinkButton button = new LinkButton { ID = "SelectAllButton", Text = "All", CausesValidation = false };
                        button.Click += this.SelectAll_Click;
                        cell.Controls.Add(button);
                        table.Rows[0].Cells.Add(cell);
                    }
                }
            }
        }

                                              
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Select allOpen in new window

 

by: b1xml2Posted on 2008-08-03 at 07:43:18ID: 22147681

By the way, the code syntax provided uses the VS2008 IDE but the code can be compiled under 2.0 or 3.x
>> new LinkButton { ID = "SelectAllButton", Text = "All", CausesValidation = false };

20120131-EE-VQP-002

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