Question

How to Echo keyboard input, store to array, and print array

Asked by: Mooligan

Hi everyone, I was hoping someone can help with an assignment from my assembly class, I'll be asking the instructor on friday but was hoping to get an answer sooner.

As the subject says, I need a chunk of code that will echo keyboard input to the screen while storing it to an array, and then being able to re-print what is stored. The actual assignment is to print it out in reverseorder but I am just trying to figure out how to get it stored in the array and then print its contents before I worry about reversing it.

So, I think I am fairly close I am just having trouble printing it, maybe I am not storing it properly? This is what I have:

declared in dseg: InitialString       DB      100 DUP(?)

My main code:

mov si, 0
ReadString:
MOV AH, 01
INT 21H
MOV bx, OFFSET InitialString
MOV [bx+si], al       ;store string
inc si
CMP al,0DH            ;check for carriage return
JE EXIT
jmp ReadString


EXIT:

mov si, 0
mov cx, 100
PrintString:
MOV ah, 02

MOV bx, OFFSET InitialString
mov dl, [bx+si]
int 21h
inc si
dec cx
loop PrintString



Please advise on where I am going wrong

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Asked On
2006-11-30 at 00:14:32ID22077467
Tags

keyboard

,

input

,

assembly

,

array

Topic

Assembly Programming Language

Participating Experts
2
Points
125
Comments
4

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Answers

 

by: dimitryPosted on 2006-11-30 at 21:56:41ID: 18051681

mov si, 0
mov cx, 100
PrintString:
MOV ah, 02

MOV bx, OFFSET InitialString
mov dl, [bx+si]
int 21h
inc si
;;;;;;;;dec cx  <- this is part of loop operator
loop PrintString

 

by: MarkRRPosted on 2006-12-04 at 02:07:40ID: 18067373

See if this helps.

declared in dseg: InitialString      DB     100 DUP(?)

My main code:

;-- Locate data segment I was using MASM directive .Data
mov ax, @data
mov ds, ax

mov si, 0
ReadString:
MOV bx, OFFSET InitialString
MOV [bx+si], al      ;store string

;-- move Int 21h call
MOV AH, 01
INT 21H

inc si
CMP al,0DH          ;check for carriage return
JE EXIT
jmp ReadString


EXIT:

mov si, 1
mov cx, 63h
PrintString:
MOV ah, 02

MOV bx, OFFSET InitialString
mov dl, [bx+si]
int 21h
inc si
;-- dec cx  not needed.
loop PrintString

MarkRR

 

by: MooliganPosted on 2006-12-25 at 21:43:48ID: 18197288

My apologies I thought I closed this. Dimitry's suggestion was right on, it led me to my solution.

20120131-EE-VQP-002

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