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6.2

TROUBLE ADDING TWO NUMBERS IN ASSEMBLY

Asked by khwajakhurram in Assembly Programming Language

Tags: assembly, numbers, two, add

I believe the disp_sum (last) call is incorrect because the program will execute but the sum will not be displayed.
Project is due tomorrow (11/27) so prompt assistance will be greatly appreciated
Thanks in advance!

; A Simple Calculator that performs basic arithmetic (+ - * /)

.model small

.stack 256

CR equ 13d
LF equ 10d

.data

promptNum1 db 'Please Enter The First Number:', 0 ;string terminated by 0
promptNum2 db CR, LF,'Please Enter The Second Number:',0 ;string terminated by 0
sum db CR, LF, 'The sum Of The Two Numbers Is:', 0 ;string terminated by 0
num1 dw ?
num2 dw ?
.code

start:

mov ax, @data ;set ds register to point to data segment
mov ds, ax ;since you cannot assign a segment to ds directy
mov ax, offset promptNum1 ;store memory address of promptNum1 in ax

call display_str ;calls the display_str to display promptNum1 string
call read_input ;read first number entered by user

mov num1, ax ;store the number entered by user into num1 variable
mov ax, offset promptNum2 ;store memory address of promptNum2 into ax

call display_str ;calls the display_str to display promptNum2 string
call read_input ;read second number entered by user

mov num2, ax ;store the second number entered by user into num2 variable
mov ax, offset sum ;store memory address of sum into ax

call display_str ;calls the display_str to display sum string

mov ax, num1 ; ax = num1 ;move contents of num1 variable to the ax register
add ax, num2 ; ax = ax + num2 ;add contents of num2 variable to the existing contents of ax

call putn ; display sum ;call putn function to display the value of sum
mov ax, 4c00h
int 21h ; finished, back to dos

display_str: ;definition of display_str which displays string terminated by 0
push ax ;save contents of register ax
push bx ;save contents of register bx
push cx ;save contents of register cx
push dx ;save contents of register dx
mov bx, ax ;store address in bx (required for display)
mov al, byte ptr [bx] ;copy address of first character in string to al register

display_loop: cmp al, 0 ;while loop, while al != 0
je display_rest ;if last result was 0, then go to display_restore
call disp_char ;display character, one at a time, while al != 0
inc bx ;loop control, bx = bx + 1
mov al, byte ptr [bx] ;display next character in string
jmp display_loop ;go back to beginning of loop

display_rest:
pop dx ;restore register to beginning value
pop cx ;restore register to beginning value
pop bx ;restore register to beginning value
pop ax ;restore register to beginning value
ret


disp_char: ;display character stored in al, called by display_loop
push ax ;save contents of register ax
push bx ;save contents of register bx
push cx ;save contents of register cx
push dx ;save contents of register dx
mov dl, al ;move contents of al into bl (required for display)
mov ah, 2h ;call DOS display subprogram
int 21h ;interrupt to call subprogram
pop dx ;restore register to beginning value
pop cx ;restore register to beginning value
pop bx ;restore register to beginning value
pop ax ;restore register to beginning value
ret

read_input: ;read character into al
mov ah, 1h ;call DOS input subprogram
int 21h ;interrupt to call subprogram
ret


disp_sum ; display string terminated by 0
; dx contains address of string
mov dh, ah
mov ah, 2h
int 21h
ret


end start
 
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[+][-]11/27/07 09:59 PM, ID: 20363519Accepted Solution

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Zone: Assembly Programming Language
Tags: assembly, numbers, two, add
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Solution Provided By: abith
Participating Experts: 1
Solution Grade: B
 
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