Question

Binary Bomb Final Phase

Asked by: pummer

I am working through the CS:APP textbook (auditing a class at the local state U) and I'm trying to complete the final phase of the binary bomb lab.  Basically, I need to figure out what string to send to this function (in C) so that the "bomb" doesn't "explode..." and all I have to work with is the assembly code.  

One way to get the answers, I've found, is to try to convert the assembly logic into C.  But here, I'm really at a loss as to what this code does... I think there's a linked list with defined nodes and then somehow they're incremented through in some kind of loop, but I can't figure out what it is I need to type in to keep the bomb from detonating.  I thought it was simply a value in one of the nodes but that doesn't seem to be working.


Anyway, here's the code.  Any help you can offer is much appreciated, I feel like my head's about to explode after going through phases 1-5 :(

08048f33 <phase_6>:
 8048f33:	55                   	push   %ebp
 8048f34:	89 e5                	mov    %esp,%ebp
 8048f36:	83 ec 18             	sub    $0x18,%esp
 8048f39:	c7 44 24 0c 00 00 00 	movl   $0x0,0xc(%esp)
 8048f40:	00 
 8048f41:	c7 44 24 08 0a 00 00 	movl   $0xa,0x8(%esp)
 8048f48:	00 
 8048f49:	c7 44 24 04 00 00 00 	movl   $0x0,0x4(%esp)
 8048f50:	00 
 8048f51:	8b 45 08             	mov    0x8(%ebp),%eax
 8048f54:	89 04 24             	mov    %eax,(%esp)
 8048f57:	e8 50 f9 ff ff       	call   80488ac <__strtol_internal@plt>
 8048f5c:	a3 2c a6 04 08       	mov    %eax,0x804a62c
 8048f61:	c7 04 24 2c a6 04 08 	movl   $0x804a62c,(%esp)
 8048f68:	e8 bb fc ff ff       	call   8048c28 <fun6>
 8048f6d:	ba 01 00 00 00       	mov    $0x1,%edx
 8048f72:	8b 40 08             	mov    0x8(%eax),%eax
 8048f75:	83 c2 01             	add    $0x1,%edx
 8048f78:	83 fa 07             	cmp    $0x7,%edx
 8048f7b:	75 f5                	jne    8048f72 <phase_6+0x3f>
 8048f7d:	8b 00                	mov    (%eax),%eax
 8048f7f:	3b 05 2c a6 04 08    	cmp    0x804a62c,%eax
 8048f85:	74 05                	je     8048f8c <phase_6+0x59>
 8048f87:	e8 67 03 00 00       	call   80492f3 <explode_bomb>
 8048f8c:	c9                   	leave  
 8048f8d:	c3                   	ret    
 8048f8e:	90                   	nop    
 8048f8f:	90                   	nop    
 
08048c28 <fun6>:
 8048c28:	55                   	push   %ebp
 8048c29:	89 e5                	mov    %esp,%ebp
 8048c2b:	56                   	push   %esi
 8048c2c:	53                   	push   %ebx
 8048c2d:	8b 4d 08             	mov    0x8(%ebp),%ecx
 8048c30:	8b 59 08             	mov    0x8(%ecx),%ebx
 8048c33:	c7 41 08 00 00 00 00 	movl   $0x0,0x8(%ecx)
 8048c3a:	89 ce                	mov    %ecx,%esi
 8048c3c:	89 c8                	mov    %ecx,%eax
 8048c3e:	89 ca                	mov    %ecx,%edx
 8048c40:	85 db                	test   %ebx,%ebx
 8048c42:	75 2a                	jne    8048c6e <fun6+0x46>
 8048c44:	eb 34                	jmp    8048c7a <fun6+0x52>
 8048c46:	89 d0                	mov    %edx,%eax
 8048c48:	8b 52 08             	mov    0x8(%edx),%edx
 8048c4b:	85 d2                	test   %edx,%edx
 8048c4d:	74 04                	je     8048c53 <fun6+0x2b>
 8048c4f:	39 0a                	cmp    %ecx,(%edx)
 8048c51:	7f f3                	jg     8048c46 <fun6+0x1e>
 8048c53:	39 d0                	cmp    %edx,%eax
 8048c55:	75 04                	jne    8048c5b <fun6+0x33>
 8048c57:	89 de                	mov    %ebx,%esi
 8048c59:	eb 03                	jmp    8048c5e <fun6+0x36>
 8048c5b:	89 58 08             	mov    %ebx,0x8(%eax)
 8048c5e:	8b 43 08             	mov    0x8(%ebx),%eax
 8048c61:	89 53 08             	mov    %edx,0x8(%ebx)
 8048c64:	89 c3                	mov    %eax,%ebx
 8048c66:	89 f2                	mov    %esi,%edx
 8048c68:	89 f0                	mov    %esi,%eax
 8048c6a:	85 db                	test   %ebx,%ebx
 8048c6c:	74 0c                	je     8048c7a <fun6+0x52>
 8048c6e:	85 d2                	test   %edx,%edx
 8048c70:	74 e1                	je     8048c53 <fun6+0x2b>
 8048c72:	8b 0b                	mov    (%ebx),%ecx
 8048c74:	39 0a                	cmp    %ecx,(%edx)
 8048c76:	7f ce                	jg     8048c46 <fun6+0x1e>
 8048c78:	eb d9                	jmp    8048c53 <fun6+0x2b>
 8048c7a:	89 f0                	mov    %esi,%eax
 8048c7c:	5b                   	pop    %ebx
 8048c7d:	5e                   	pop    %esi
 8048c7e:	5d                   	pop    %ebp
 8048c7f:	90                   	nop    
 8048c80:	c3                   	ret
                                  
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Asked On
2008-05-05 at 06:39:37ID23376350
Tags

Assembly

Topics

Assembly Programming Language

,

C Programming Language

Participating Experts
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Answers

 

by: Infinity08Posted on 2008-05-05 at 06:58:05ID: 21500049

>> I think there's a linked list with defined nodes and then somehow they're incremented through in some kind of loop,

That's what happens indeed. There is a linked list in memory, and the code is going through the linked list, stopping at a certain node (which node ?)


>> but I can't figure out what it is I need to type in to keep the bomb from detonating.

Watch the condition for the explosion :

 8048f7f:       3b 05 2c a6 04 08       cmp    0x804a62c,%eax
 8048f85:       74 05                   je     8048f8c <phase_6+0x59>
 8048f87:       e8 67 03 00 00          call   80492f3 <explode_bomb>

How can you avoid that it explodes ?

 

by: pummerPosted on 2008-05-05 at 14:46:59ID: 21503287

Wow, thanks for giving me such an obvious solution -- all along I didn't realize you could set breakpoints at a particular address, I thought you could only set them at function calls. D'OH!

20120131-EE-VQP-002

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