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8.8

Exponential function in assembler

Asked by kayahr in Assembly Programming Language, C Programming Language

I have the following scenario: I have an input byte (IN) with the value 0-255 in it and I want to calculate a 2-byte output word (OUT) from it which should grow in an exponential way.  So IN=0 must result in OUT=0 (or near 0) and IN=255 must result in OUT=65535 (Or near that value). The results between these two min/max values must be exponential and not linear.

The results must not be exact. So if OUT is 65500 when IN is 255 then this is also ok.  In C I tried the formular OUT = IN * IN and the result is ok for me. The problem is, the binary gets too large with this formular (I'm compiling for an embedded chip (AVR) with 2KB RAM). So I'm searching for a very very small Assembler code which does something similiar to OUT=IN*IN but may fit into the last few bytes I have left in the chip.

The assembler dialect and architecture doesn't matter, I hope I can get the idea anyway. C code is also fine when it can be compiled into a binary small enough.
 
[+][-]12/13/08 01:22 PM, ID: 23165501Expert Comment

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[+][-]12/13/08 11:12 PM, ID: 23166895Accepted Solution

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Zones: Assembly Programming Language, C Programming Language
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Solution Provided By: ozo
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[+][-]12/14/08 11:03 PM, ID: 23171526Author Comment

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[+][-]12/15/08 12:45 AM, ID: 23171817Expert Comment

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[+][-]10/12/09 01:40 AM, ID: 25549408Expert Comment

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