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binary bomb

Asked by 2xexit in Assembly Programming Language, Unix Systems Programming

Tags: phase_2

i can't slove it .. i  have to slove it tomorrow...help me..

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08048b6a <phase_2>:
 8048b6a:       55                      push   %ebp
 8048b6b:       89 e5                   mov    %esp,%ebp
 8048b6d:       53                      push   %ebx
 8048b6e:       83 ec 34                sub    $0x34,%esp
 8048b71:       8d 45 d8                lea    0xffffffd8(%ebp),%eax
 8048b74:       89 44 24 04             mov    %eax,0x4(%esp,1)
 8048b78:       8b 45 08                mov    0x8(%ebp),%eax
 8048b7b:       89 04 24                mov    %eax,(%esp,1)
 8048b7e:       e8 89 03 00 00          call   8048f0c <read_six_numbers>
 8048b83:       bb 01 00 00 00          mov    $0x1,%ebx
 8048b88:       8b 44 9d d4             mov    0xffffffd4(%ebp,%ebx,4),%eax
 8048b8c:       83 c0 05                add    $0x5,%eax
 8048b8f:       39 44 9d d8             cmp    %eax,0xffffffd8(%ebp,%ebx,4)
 8048b93:       74 05                   je     8048b9a <phase_2+0x30>
 8048b95:       e8 16 09 00 00          call   80494b0 <explode_bomb>
 8048b9a:       43                      inc    %ebx
 8048b9b:       83 fb 05                cmp    $0x5,%ebx
 8048b9e:       7e e8                   jle    8048b88 <phase_2+0x1e>
 8048ba0:       83 c4 34                add    $0x34,%esp
 8048ba3:       5b                      pop    %ebx
 8048ba4:       5d                      pop    %ebp
 8048ba5:       c3                      ret
 
 
08048f0c <read_six_numbers>:
 8048f0c:       55                      push   %ebp
 8048f0d:       89 e5                   mov    %esp,%ebp
 8048f0f:       83 ec 28                sub    $0x28,%esp
 8048f12:       8b 55 0c                mov    0xc(%ebp),%edx
 8048f15:       8d 42 14                lea    0x14(%edx),%eax
 8048f18:       89 44 24 1c             mov    %eax,0x1c(%esp,1)
 8048f1c:       8d 42 10                lea    0x10(%edx),%eax
 8048f1f:       89 44 24 18             mov    %eax,0x18(%esp,1)
 8048f23:       8d 42 0c                lea    0xc(%edx),%eax
 8048f26:       89 44 24 14             mov    %eax,0x14(%esp,1)
 8048f2a:       8d 42 08                lea    0x8(%edx),%eax
 8048f2d:       89 44 24 10             mov    %eax,0x10(%esp,1)
 8048f31:       8d 42 04                lea    0x4(%edx),%eax
 8048f34:       89 44 24 0c             mov    %eax,0xc(%esp,1)
 8048f38:       89 54 24 08             mov    %edx,0x8(%esp,1)
 8048f3c:       c7 44 24 04 98 98 04    movl   $0x8049898,0x4(%esp,1)
 8048f43:       08
 8048f44:       8b 45 08                mov    0x8(%ebp),%eax
 8048f47:       89 04 24                mov    %eax,(%esp,1)
 8048f4a:       e8 4d f9 ff ff          call   804889c <_init+0x178>
 8048f4f:       83 f8 05                cmp    $0x5,%eax
 8048f52:       7f 05                   jg     8048f59 <read_six_numbers+0x4d>
 8048f54:       e8 57 05 00 00          call   80494b0 <explode_bomb>
 8048f59:       89 ec                   mov    %ebp,%esp
 8048f5b:       5d                      pop    %ebp
 8048f5c:       c3                      ret
[+][-]05/09/09 01:04 AM, ID: 24342790Expert Comment

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