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8.3

Convert and output decimal to hex using MARS 3.7

Asked by skylark24 in Assembly Programming Language

I'm trying to finish a program that prompts the user for an integer and outputs the number in hex format.  Yes...this is for an assignment, but I'm looking for some suggestions on which lines my trouble is occuring.  Lines 71 to 93 are commented and the students are to supply the appropraite instructions.  0..9 worked until I added 75,76,84,85(marked w/ ****)
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# Author: Summer Armitage
# Date:   September 12, 2009
#
# A MIPS program that will convert an integer into a hexadecimal number.
# Students must add the missing lines of code.
 
 
        .data
 
Prompt:
        .asciiz "Enter an integer: "
 
Output1:
        .asciiz "The decimal number "
        
Output2:
        .asciiz " is 0x"
 
Output3:
        .asciiz " in hexadecimal."
 
        
        .text
 
# Get input from user.  First, issue a prompt using the
# system call that will print out a string of characters.
 
        la $a0, Prompt  # Put the address of the string in $a0
        li $v0, 4
        syscall
 
# Next, make the system call that will wait for the user to input
# an integer.
 
        li $v0, 5  # Code for input integer
        syscall
 
# Integer input comes back in $v0
# Save the inputted integer in a saved register - important!
# It cannot stay in $v0 as we need to reuse $v0.
 
        move $s0, $v0
 
# Next, begin to output the result message.  This is done in several
# steps, including outputting strings and the original integer.
 
# Output first string.
        
        la $a0, Output1
        li $v0, 4
        syscall
 
# Output original integer
        
        move $a0, $s0  # Remember, $s0 contains the input number.
        li $v0, 1
        syscall
 
# Output second string.
        
        la $a0, Output2
        li $v0, 4
        syscall
 
# Output the hexadecimal number.  (This is done by isolating four bits
# at a time, adding them to the appropriate ASCII codes, and outputting
# the character.  It is important that the digits are output in
# most-to-least significant bit order.
        
 
        li $s1, 32           # Set up a loop counter
Loop:  
        rol $s0, $s0, 4           # Roll the bits left by four bits - wraps highest bits to lowest bits (where we need them!)
        and $t0, $s0, 4           # Mask off low bits (logical AND with 000...01111)
        slti $t1, $t0, 10           # Determine if the bits represent a number less than 10 (slti)***
        beq $t1, $zero, MakeHighDigit          # If not (if greater than 9), go make a high digit****
                 
 
MakeLowDigit:           
        add $t0, $t0, 48          # Combine it with ASCII code for '0', becomes 0..9 
        move $a0, $t0          # Go output the digit
 
MakeHighDigit:
        #sub $t2, $t0, 10          # Subtract 10 from low bits****
        #add $t0, $t2, 65          # Add them to the code for 'A' (65), becomes a..f***
 
DigitOut:
        move $a0, $t0      # Output the ASCII character
        li $v0, 11
        syscall
        
        subi $s1, $s1, 1             # Decrement loop counter
        bne $s1, $zero, Loop             # Keep looping if loop counter is not zero
 
# Output third string.
        
        la $a0, Output3
        li $v0, 4
        syscall
        
        
# Done, exit the program
 
        li $v0, 10  # This system call will terminate the program gracefully.
        syscall
[+][-]09/14/09 01:32 AM, ID: 25323599Accepted Solution

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Zone: Assembly Programming Language
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Solution Provided By: Infinity08
Participating Experts: 1
Solution Grade: B
 
[+][-]09/14/09 12:30 PM, ID: 25328500Author Comment

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