Solved: test if a number is greater than 0

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kuntilanak🇺🇸

test if a number is greater than 0

if I have a 32 bit number in MIPS, I want to extract the sign bit of that number (0 or 1). How can I do this using logical operators? I want the end result either to be 0 or 1.

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d-glitch🇺🇸

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kuntilanak🇺🇸

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yes, it's two's complement and it has a sign bit as well.. at position 31...

how do I extract this 31 bit and put it to one bit variable called result?

kuntilanak🇺🇸

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does shifting the 32 bit two's complement 31 times work?

d-glitch🇺🇸

Depends on how the shift is implemented. There may be more than one type of shift available.

I don't know if they shift in 1's, 0's, or copies of the MSB

A circular shift 1-bit to the right and anding the 31 MSB with 0's could work too.

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kuntilanak🇺🇸

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the shift add's 0 to the MSB...

kuntilanak🇺🇸

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it's verilog(VHDL) right shift if you are familiar with

d-glitch🇺🇸

I am not too familiar with VHDL yet, but you certainly have direct access to individual bits.

You should be able to say sometihing like

Result = !Number[31] where ! is negation and [31] is the index.

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kuntilanak🇺🇸

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what if I want to know if a 32 bit is greater than 0? the above is for greater or equal than 0... any easy way to do this?

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Tursilion🇺🇸

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