I want to know that how can I make a program of finding the equivlent resistance of a circuit of resistances,and to find the current in each branch.
If some one can provide me the algorithm,than I'll be thankful to him.
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i wud suggest using directed graph to represent ur circuit..
then the problem lies in identifying triangles ( as obg mentioned) ..
and if i remember it correctly .. u will also have to specify the two points between which u want to know the resistance ..
for that we better first get one good algorithm .. then we can help in further coding ..
i'll see if i can find one
I am using linked stack to represent the circuit.In that,I'm storing the value,starting coordinates and ending co-or.in the value part of link list.
The resistances having same coordinates are said to be joined ,otherwise not.
For this time,assume only one battery to be there.
I hope obq,now u can give any suggestion.
Ok, then I suppose the easy part is to go through the list (or stack) and for each resistor loop through the following resistors to see if anyone has the same coordinates. If one is found, calculate the equivalent parallel resistance, set it in the found resistor, and remove the current; Something like
void replace_parallels(struct resistor **stack)
{
struct resistor *r, *t = NULL;
if (*resistor != NULL) {
for (r = (*stack)->next; r; r = r->next)
if (is_parallel(r, *stack)) { /* "same coordinates" */
r->resistance = 1.0 / (1.0 / r->resistance + 1.0 / (*stack)->resistance);
/* done with r, delete current */
t = *stack;
*stack = t->next;
free(t);
break;
}
if (t) /* if current is removed */
replace_parallels(stack);
else
replace_parallels(&(*stack
}
}
Similarily, you have to find the serially connected resistors. Just make sure that you don't have any other crap hanging between them
void replace_serials(struct resistor **stack)
{
struct resistor *r, *t = NULL;
if (*resistor != NULL) {
for (r = (*stack)->next; r; r = r->next)
if (is_serial(r, *stack)) { /* && NOTHING on the middle coordinate! */
r->resistance += (*stack)->resistance;
/* done with r, delete current */
t = *stack;
*stack = t->next;
free(t);
break;
}
if (t) /* if current is removed */
replace_serials(stack);
else
replace_serials(&(*stack)-
}
}
... might be something to start with? Of course I haven't tried any of this, but it should work (at least with minor adjustments).
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by: obgPosted on 2002-12-03 at 00:56:43ID: 7524298
That is not so easy using plain C code. The 50 pts answer would be something like: Use Spice/PSpice or similar...
It would help to know if you have made some progress at all, codewise. What is your internal structure for representing the resistor network?
My first suggestion is to iterate through an algorithm that adds up serially connected resistors and then does the same for those in parallel. This is not enough though, since you'll probably end up with some triangular (or worse maybe) cofiguration. The problem is to identify those and using the existing formulas (which I don't remember) for resolving them...