Convert double value to char *

hello,

is there a quick solution to convert a double value to char* ?
my dll takes a double array from a vba interface and i must use a method which takes these values as a char * array. as i manage only the middle i must find a solution to do the convertion.

i've some code but i'm afraid it to be long and when i go out from DoubletoChar lnRes is null.

#include <stdlib.h>
#include <stdio.h>
#include <string.h>

void main( void )
{
     double lnDouble = -3.1415926535;
     char * lsRes = NULL;
     int lnRep = 0;

     lnRep = DoubleToChar(lnDouble, lsRes);
     printf("resultat : %s\n", lsRes);
}

int DoubleToChar(double pnDouble, char *psBuffer) {
     int lnDecimal = 0;
     int lnSign = 0;
     int lnI = 0;

     psBuffer = _fcvt(pnDouble, 15, &lnDecimal, &lnSign );

     for (lnI = strlen(psBuffer); lnI >= lnDecimal; lnI--) {
          psBuffer[lnI + 1] = psBuffer[lnI];
          if (lnI == lnDecimal)
               psBuffer[lnI] = '.';
     }

     if (lnSign == 1) {
          for (lnI = strlen(psBuffer); lnI >= 0; lnI--) {
               psBuffer[lnI + 1] = psBuffer[lnI];
               if (lnI == 0)
                    psBuffer[lnI] = '-';
          }
     }

     return 1;
}

what can i do to have the good value in lnRes and to go faster(i may have to convert an array of 1000 values one by one)Start Free Trial