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6.0

replace function efficiency

Asked by sizak in C Programming Language

Tags: char, malloc

Hey guys need a lil help/opinion on this. this code is being used and heres the senario.. find and replace a tag in a body of text. now its alright for small things but try when it has to do it 3 million times over and over replacing it once or up to 25 times. heres the replace function right now

str is the buffer(text), code is the tag in the text and then val is what needs to be in place of the code.. an example of the function in use is

res=replace(res,"%%CODE%%",zak);

so %%CODE%% would be replaced with zak and then return'd.

char * replace(char * str,char *code,char * val){
char * needle;
char * tmpstr;
bool changed;

tmpstr=(char *) malloc(strlen(str)+strlen(val)*4086);

changed=true;
while(changed ) {
changed=false;
needle=strstr(str,code);
if (needle!=NULL) {
changed=true;
memcpy(tmpstr,str,needle-str);
tmpstr[needle-str]=0;
strcat(tmpstr,val);
strcat(tmpstr,needle+strlen(code));
strcpy(str,tmpstr);
};
};
free(tmpstr);

return str;
};

this would be a HUGE help to me thanks guys

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replace function efficiency

Asked by sizak in C Programming Language

Tags: char, malloc

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