Hi iismatt,
Try the following:
typedef struct{
char myString[99];
} myStruct;
myStruct arrayOfStructs[10];
David Maisonave :-)
Cheers!
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Question
An Array of structs
Guys (and girls),
Two questions. Basically, I want to design an array of structs in C. And in these structs I want dynamic string allocation. I'm having major problems implementing this in the C language. Can anyone tell me where I'm going wrong?
My code would look something like this...
Struct {
char myString[];
} myStruct;
myStruct arrayOfStructs[10];
Without even taking the dynamic strings within the structs into account, I can't get my program to recognize myStruct as a valid type. What am I missing?
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Answers
>>>
You can't have an array of indeterminate size in a structure. The usual approach would be to put a pointer in the structure and set the pointer to point to some dynamically allocated memory.
>>>
char[] myString; is syntactically equivalent to char* myString;
the s in "struct" must be lowercase. Axter's post has the syntax you're looking for. :)
If you want to use your approach of char[] myString, you're going to need to allocate memory individually for each pointer using malloc/calloc.
The keyword struct needs to be lowercase.
You can either do a typedef as in my above example, or you need to use the keyword struct when you declare a variable of that type.
Example:
struct myStruct2{
char myString[99];
};
struct myStruct2 arrayOfStructs2[10];
You could also declare a single instance of struct via following method:
struct{
char myString[99];
} myStruct3;
The above is a single instance of a struct which declares the type, and the variable name for it (myStruct3).
Example usage with pointer, as previous experts have suggested.
#include <memory.h>
typedef struct{
char *myString;
int string_size;
} myStruct;
myStruct arrayOfStructs[10];
int main(int argc, char* argv[])
{
int i;
for(i = 0;i < sizeof(arrayOfStructs) / sizeof(arrayOfStructs[0]);
{
arrayOfStructs[i].myString
arrayOfStructs[i].string_s
memset(arrayOfStructs[i].m
}
>>char myString[]; is an invalid declaration in C, but for some reason if you put that inside of a struct declaration, it compiles; in that case I think char myString[] IS
>>equivalent to char* myString; but I'm not 100% positive.
That depends on your compiler. It doesn't compile on MS VC++ 6.0, but it does compile on GNU 3.x and Bordland 5.5.1.
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by: efnPosted on 2005-04-10 at 19:34:03ID: 13750029
You can't have an array of indeterminate size in a structure. The usual approach would be to put a pointer in the structure and set the pointer to point to some dynamically allocated memory.