Question

File open - counting chars

Asked by: Jasbir21

Hi,
I have written a small program to gain understanding to how file opens works..
The program counts the number of characters and lines in the file...
I found it strange as in the test.txt file I had the following:
Hello
Everyone
Testing
And the number of counts of characters i got was : 26
And the number of  new lines i got was: 0
Now, if i count character one by one, it is should be 20 ( 5 chars for Hello + 8 chars for Everyone and 7 chars for Testing)
Now,if i count how many new lines i got , it should be 3:

What is could go wrong :-(

int countChar(char *,int *)
int main()
{
int c;
int *lCount;
lCount=malloc(sizeof(int));
c=countChar("test.txt",lCount);

printf("The number of char counts : %d\n",c);

printf("The number of new lines : %d\n",*lCount);

return 0;

}

int countChar(char *f,int *lCount)
{
int count=0;
FILE *fp;
int ch;
fp=fopen(f,"r+");
if(fp==NULL)
return -1;

while((ch=fgetc(fp))!=EOF)
{
if(ch=='\n')
*lCount++;

count++;
}
return count;

}

Also, is there any function in C that allows to count word . i.e Hello - 1 word Everyone - 1 word
thanks

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Asked On
2007-05-27 at 22:23:40ID22597647
Tags

c

,

file

,

counting

Topic

C Programming Language

Participating Experts
3
Points
125
Comments
12

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Answers

 

by: ozoPosted on 2007-05-27 at 22:33:45ID: 19166192

(*lCount)++;

 

by: nixfreakPosted on 2007-05-27 at 22:40:50ID: 19166207

> Now, if i count character one by one, it is should be 20 ( 5 chars for Hello + 8 chars for Everyone and 7 chars for Testing)

You are also counting \0 and \n for every line.

 

by: nixfreakPosted on 2007-05-27 at 22:44:57ID: 19166212

> Also, is there any function in C that allows to count word . i.e Hello - 1 word Everyone - 1 word

You can use the fact that a word is a non zero length string of chars delimited by whitespace

 

by: Jasbir21Posted on 2007-05-27 at 23:02:59ID: 19166244

Hi ,
Thanks a lot...
In the file, i realized i had three extra lines...
Hello
Everyone
Testing


So, that was also , being counted... :-(
Since, my count is now 23, is that the new line is being counted and not '\0' or is it '\0' being counted and not '\n'

 

by: ozoPosted on 2007-05-27 at 23:07:42ID: 19166252

*lCount++; means *(lCount++);
you want (*lCount)++;

 

by: ozoPosted on 2007-05-27 at 23:09:54ID: 19166254

You should probably also initialize *lCount somewhere.

 

by: Jasbir21Posted on 2007-05-27 at 23:31:08ID: 19166303

Hi,
Thanks a lot
I initialized *lCount in the main function...
Also, I changed to (*lCount)++ in cc function...

But now, for counts which involves characters only, I am getting 25 ...(Since all the word would have '\0' and new line, i thnk it should be 26...) .This is so confusing :-(

But for the lines, I am getting correct answer which is 3..
Hello
Everyone
Testing

 

by: nixfreakPosted on 2007-05-27 at 23:41:52ID: 19166321

You can find a good implementation of what your program in the source code for the "wc" utility on any unix/linux. Read the man page first before you read the code.

 

by: Infinity08Posted on 2007-05-27 at 23:52:20ID: 19166337

Forget about the '\0' ... There are no '\0' in text files. The extra characters counted were all '\n' (or possibly '\r' or extra spaces or ...).

To find out which characters were read, you can write each character once you read it like this :

        printf("%02x ", ch);   /* <--- put this in the while loop */

If you want, you can paste your program's output here, and we can tell you why it counts 25 ...



And here's the corrected code :

int countChar(char *, int *);     /* <--- you forgot a ; at the end of this line */

int main() {
    int c = 0;                /* <--- it's always good to initialize your variables once you declare them */
    int lCount = 0;       /* <--- don't make this a pointer - you don't need to (the malloc line can then go too) */
    c = countChar("test.txt", &lCount);   /* <--- and instead we pass the address of lCount */

    printf("The number of char counts : %d\n", c);
    printf("The number of new lines : %d\n", lCount);   /* <--- we can simply show lCount now ... */

    return 0;
}

int countChar(char *f, int *lCount) {
    int count = 0;
    FILE *fp = 0;
    int ch = '\0';
    fp = fopen(f, "r+");
    if (fp == NULL)
        return -1;

    while ((ch = fgetc(fp)) != EOF) {
        if (ch == '\n')
            (*lCount)++;              /* <--- see ozo's comments */
        count++;
    }
    return count;
}


Note that I indented your code to make it better readable. I commented the modifications I made. Some are to make your life easier (like the malloc), some are to avoid bugs (like initializing the variables once they are declared), and others are to fix errors (like the fix already made by ozo).

 

by: Jasbir21Posted on 2007-05-28 at 03:24:07ID: 19166791

Hi,

Thanks a lot...

I put %02x...and this is the output..
48656c6c6f200a45766572796f6e65200a54657374696e670a

 

by: Jasbir21Posted on 2007-05-28 at 03:58:52ID: 19166850

Hi,
I am trying to use the same concept for counting words..but i am getting an infinite loop...
I used my friends account to post the question ...kindda ran out of points...
Pls look at it...it is related to counting words in a file..

 

by: Infinity08Posted on 2007-05-28 at 06:39:11ID: 19167269

>> 48656c6c6f200a45766572796f6e65200a54657374696e670a

That means you have these characters :

      "Hello \nEveryone \nTesting\n"

Notice the two spaces after "Hello" and "Everyone"


>> I am trying to use the same concept for counting words..but i am getting an infinite loop...

What's the code you used ?

20120131-EE-VQP-002

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