Simply, i want to know how to sort (simply 3) letters.. What is the idea behind of this, i can easly sort numbers but i can not letters.
ex:
b
c
a
result :
a
b
c
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>> You just need to treat the letters as numbers by typecasting them.
You don't need to typecast them at all ... characters are just numbers to the compiler, so you can just do :
char first_char, second_char;
if (first_char < second_char) {
/* first_char comes before second_char alphabetically */
}
else {
/* first_char comes after second_char alphabetically or they are the same characters */
}
Or you could use the standard functions
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define SIZE(A) sizeof(A)/sizeof(A[0])
int myCmp(const void* a, const void* b)
{
return strcmp((char*)a, (char*)b );
}
int main(int argc, char *argv[])
{
char arr[] = {'c', 'b', 'a'};
int i=0;
for(; i<SIZE(arr); ++i)
printf("%c ", arr[i]);
puts(" ");
qsort(arr, SIZE(arr), sizeof(arr[0]), myCmp);
i=0;
for(; i<SIZE(arr); ++i)
printf("%c ", arr[i]);
puts(" ");
return 0;
}
http://www.cplusplus.com/r
http://www.cplusplus.com/r
>> return strcmp((char*)a, (char*)b );
strcmp ??? That's not a very good way of doing it, since there is no terminating NULL, just one character. What happens if both characters are the same ? Yes, indeed ... you might crash your program.
And also : qsort is a bit overkill for sorting three characters, don't you think ?
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by: archang3lPosted on 2007-09-16 at 03:08:31ID: 19900089
Hello thefirstfbli,
You mentioned you know how to sort numbers already. You just need to treat the letters as numbers by typecasting them.
i.e.
char a = 'a';
char b = 'b';
(int)a; // 65
(int)b; // 66
Regards,
archang3l