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8.3

Segmentation fault with string operations - help needed

Asked by flasht in C Programming Language

Hello,
First of all - I am not a C programmer, have no idea about this and it's really hard for me to understand all those memory problems (i'm working on delphi/php).

My problem is that i got 2 long, defined strings:

char * string1 = "something really long (about 1k of characters)"
char * string2 = "something as long or even longer"

Got function:

char *replace_str(char *str, char *orig, char *rep){
  static char buffer[1024];
  char *p;
   
  if(!(p = strstr(str, orig)))
    return str;
      
  strncpy(buffer, str, p-str);
  buffer[p-str] = '\0';
          
  sprintf(buffer+(p-str), "%s%s", rep, p+strlen(orig));
            
  return buffer;
}

And what I'm willing to do is to replace few things in string1 and string2 and then marge them to string1 ... it may be important that i need to place length of string2 after all replacements in string1, because its http request and i need content-length.

But every single way i try i get segmentation fault or memory corruption later in program...

My last try was something like this (i know its really sh**tty code but as I said i have no idea what I am doing):

  char dlugosc[32];
  char *dlu = &dlugosc[0];
  char * tempstr;

  itoa (strlen(logindata), dlu);
  tempstr = malloc(sizeof(replace_str(login, "$dlul", dlu)));
  strcpy(tempstr,replace_str(login, "$dlul", dlu));
  login = realloc(login,sizeof(tempstr)+sizeof(logindata));
  strcpy(login,tempstr);
  strcat(login, logindata);
 

It's shorter example where string2 doesnt need to have anything replaced, but it does work neither.

Could anybody help me with that?
[+][-]06/02/09 11:16 AM, ID: 24529762Accepted Solution

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Zone: C Programming Language
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Solution Provided By: Infinity08
Participating Experts: 3
Solution Grade: A
 
[+][-]06/02/09 12:33 AM, ID: 24524450Expert Comment

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