Question

Hi guys, can you please check one small error in my small programme.............

Asked by: Sambho

Hi guys,
             Greetings,   I have written a small code for displaying max value, min value, and median of the inputed numbers.       I am getting .0000 behind all the numbers. I think I am getting these because I declared array as float. But I don't want those ( except where they are required) .0000, they are kind of annoying to eyes.

      Please guys can you give me tips to remove those 00000s.
Thank you.
                    

#include<stdio.h>
 
float func_mean(float array[], int n);
float largest(float array[], int n);
float smallest(float array[], int n);
 
int main(){
       
       int n = 0;
       int i;
       float array[50];
       float  mean;
       
      
       printf("\nPlease enter the elements: Note:-Please enter 0 to end inputing the numbers.\n");
             for ( i=0; i<50; i++){
             scanf ("%f",&array[i]);
             if (array[i] == 0)
             break;
             n += 1;
             };
             printf("\nThe number of element you entered is %d", n);
             printf("\n");
             printf("\nThe numbers you entered are:\n");
             for (i=0; i<n; i++)
             printf("\n%f", array[i]);
             printf("\n");
             printf("\nThe largest element you entered is %f\n", largest(array, n));
             printf("\nThe smallest element you enterd is %f\n", smallest(array,n));
             mean = func_mean(array, n);
       printf("\nThe mean you want to calculate is %f", mean);
       
       }
       
       float func_mean(float array[], int n){
             
             int i;
             float sum=0, mean;
             for ( i=0; i<n ; i++ )
                 sum = sum + array[i];
             mean = (sum/n);
             return(mean);
             }           
 
      float largest(float array[], int n){
            
            int i;
            float max;
            max = array[0];
            for (i=1; i<n; i++)
              if (max < array[i])
                  max = array[i];
            return(max);
            }
            
       float smallest(float array[], int n) {
             
             int i;
             float min;
             min = array[0];
             for (i=1; i<n; i++)
               if (min > array[i])
                  min = array[i];
             return(min);
             }

                                  
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Asked On
2009-10-15 at 14:09:53ID24816429
Topics

C Programming Language

,

C++ Programming Language

Participating Experts
2
Points
500
Comments
3

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Answers

 

by: Infinity08Posted on 2009-10-15 at 14:16:11ID: 25584990

You can specify how many digits you want after the decimal point using for example %.2f for 2 digits after the decimal point.

 

by: themrrobertPosted on 2009-10-15 at 14:21:36ID: 25585039

You have to use code like:

if(val==(int)val)
  printf("This number is an integer %i  \n",(int)val);
else
  printf("This number is still a float %f  \n",val);

 

by: Infinity08Posted on 2009-10-15 at 14:30:48ID: 25585118

If that's the kind of distinction you want to make, then you're better off using modf :

        http://cplusplus.com/reference/clibrary/cmath/modf/

to split up the floating point value in its integer part and fractional part. You can then check whether the fractional part is reasonably close to 0. something like below.

Using the == operator to compare floating point values is not likely to give the expected result.

double value;
 
double integ, fract;
fract = fmod(value, &integ);
if ((fract - 0.0) < 0.00001) {
  /* close enough - you can treat the value as an integer */
}
else {
  /* show the value as a floating point value */
}

                                              
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